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Fittoniya [83]
3 years ago
5

A metal(ii) ion solution of unknown concentration shows an absorbance of 0.55. what is the molar concentration of the metal (ii)

ion in the sample
Chemistry
1 answer:
torisob [31]3 years ago
4 0
Cover with metal .Any elements other than hydrozen and helium concentration shows an absorbance
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A chemist combine did 3.50g of potassium level with chlorine gas to yield 6.6 7g of potassium for it. Assuming all the potassium
slega [8]

Answer: mass of chlorine reacted is 3.18 g

Explanation:

2 K + Cl2 = 2KCl

no. of moles of K = mass / molar mass

= 3.50 / 39

= 0.0897

no. of moles of KCl = mass / molar mass

= 6.67 / 74.5

= 0.0895  

no. of moles of Cl2 required = number of moles of KCl / 2

= 0.0895 / 2

= 0.0448 moles  

mass of Cl2 required = no. of moles of Cl2 required x molar mass

= 0.0448 x 71

= 3.1808 g ≈ 3.18 g

Therefore mass of chlorine reacted is 3.18 g

4 0
3 years ago
What is the independent variable?
olganol [36]
X is always the independent variable
6 0
4 years ago
What is the mass of 2.35 x 10^21 moles of sodium
lora16 [44]

Answer:

5.41 x 10²² g

Explanation:

Data Given:

no. of moles of sodium = 2.35 x 10²¹ moles

mass of sodium = ?

Solution:

Formula used

         no. of moles = mass in grams / molar mass

To find mass rearrange the above equation:

   mass in grams = no. of moles x molar mass. . . . . . (1)

  • molar mass of Sodium (Na) = 23 g/mol

Put values in equation 1

          mass in grams = 2.35 x 10²¹ moles x 23 g/mol

          mass in grams =  5.41 x 10²² g

So,

mass of Sodium (Na) =  5.41 x 10²² g

8 0
4 years ago
Help plz already know 1&2
Aleonysh [2.5K]
3. A
4. B
5. A
6. E
7. A
8. C
9. A
10. B
Some of these were guesses but they were educated guesses. Best of luck. If some of them are wrong I am sorry.  <span />
3 0
3 years ago
6. The energy of a photon of light is given by E = hc/Where h = Planck's constant (6.626 x 10-34 Jsec), c = the speed of light
11111nata11111 [884]

Answer:The answers are on the attachments.

Explanation:

6 0
3 years ago
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