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2 years ago

5

A metal(ii) ion solution of unknown concentration shows an absorbance of 0.55. what is the molar concentration of the metal (ii)

ion in the sample

1 answer:

torisob [31]2 years ago

4 0

Cover with metal .Any elements other than hydrozen and helium concentration shows an absorbance

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What does the period number indicate on periodic table

anastassius [24]

It’s atomic mass is what the number means.

4 0

3 years ago

Read 2 more answers

The beakers in the picture above are labeled according to the ionic solutions they contain. What metal or metals could replace c

tangare [24]

Explanation:

When a metal replaces another metal in solution, we say such a reaction has undergone a single displacement reaction.

In such a reaction, metal higher up in the activity series replaces another one due to their position.

To known the metal or metals that will replace the given copper, we need to reference the activity series of metals.

Every metal higher than copper in the series will displace copper from the solution.

So, there metals are: potassium, sodium, lithium, barium, strontium etc.

8 0

2 years ago

Does a displacement reaction take place in 'magnesium + lead nitrate'? and if so why?

cestrela7 [59]

Answer:

Maybe or maybe not (not sure)

Explanation:

A displacement reaction is a type of reaction where one element is displaced by another from a compound.

In the case of magnesium and lead nitrate, magnesium is more reactive than lead. Therefore, it will displace lead from lead nitrate to form magnesium nitrate and lead.

The reaction can be represented as:

Mg(s) + Pb(NO3)2(aq) → Mg(NO3)2(aq) + Pb(s)

Another answer could be;

A displacement reaction does not take place in 'magnesium + lead nitrate' because magnesium is more reactive than lead.

5 0

1 year ago

The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure

Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate $\Delta H_{vap}$ of the reaction, we use clausius claypron equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = vapor pressure at temperature $T_1$

$P_2$ = vapor pressure at temperature $T_2$

$\Delta H_{vap}$ = Enthalpy of vaporization

R = Gas constant = 8.314 J/mol K

1) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =363 K

$T_2$ = final temperature =373 K

$P_2=1 atm, P_1=?$

Putting values in above equation, we get:

$\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]$

$P_1=0.69671 atm \approx 0.6970 atm$

The vapor pressure at temperature 363 K is 0.6970 atm

2) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =373 K

$T_2$ = final temperature =383 K

$P_1=1 atm, P_2?$

Putting values in above equation, we get:

$\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]$

$P_2=1.4084 atm \approx 1.410 atm$

The vapor pressure at 383 K is 1.410 atm

8 0

3 years ago

State the phenomenon exhibited by the two atoms<br>

Volgvan

Answer:

<u><em>METALS</em></u>

Lose their valence electrons easily/ ionic by electron loss.

<u><em>NOMETAL</em></u>

Gain or share valence electrons easily/ ionic by electron grain.

6 0

2 years ago