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Elis [28]
3 years ago
8

If the man has initial velocity of 0.4 m/s, acceleration is 0.343 m/s^2, a time of 5.8 seconds, and experimental final velocity

of 2.4 m/s? What is the calculated final velocity?
Group of answer choices

2.15 m/s

2.39 m/s

3.25 m/s

3.49 m/s
Physics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

The answer is going to be C.

Explanation:

Trust me. Im an expert in physics

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Aligned magnetic domains are only present in which of the following?
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Answer:

i think c

Explanation:

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3 years ago
What is lever means,types of lever.. <br>will give brainles​
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Explanation:

A lever is a rigid bar which moves freely about a fixed point called fulcrum....

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3 0
1 year ago
Roughly to what height would a 5 kg stone need to be raised in order to have the same stored energy as the energy stored in the
hoa [83]

8.16m is the required height, a 5kg stone need to be raised.

One sort of potential energy is gravitational potential energy, which is equal to the product of the object's mass (m), the gravitational acceleration (g), and the object's height (h) as measured in relation to the ground's surface (the body).

We obtain the formula by considering the work done in raising a mass m through a height h.

Work in elevating mass m through height h is equal to force times distance.

The force must be greater than the mass m's weight, hence F = mg.

Work done = mgh = gravitational potential energy

Energy =  Mass of the object × gravitational acceleration × height.

Mass of the stone = 5kg

Equating ;

∴ 400 J = 5 kg × 9.8 m/s² × height

  Height = 8.16 m

Therefore, 8.16m is the required height.

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8 0
2 years ago
The acceleration due to gravity on the surface of Jupiter is about 2.5 times the acceleration due to gravity on Earth’s surface.
Ann [662]

Answer: The correct answer is option C.

Explanation:

Weight = Mass × Acceleration

Let the mass of the space probe be m

Acceleration due to gravity on the earth = g

Weight of the space probe on earth = W

W=m\times g

Acceleration due to gravity on the Jupiter = g' = 2.5g

Weight of the space probe on earth = W'

W'=mg'=m\times 2.5g

\frac{W'}{W}=\frac{m\times 2.5g}{m\times g}

W'=2.5\times W

The weight of the space probe on the Jupiter will be 2.5 times the weight of the space probe on earth.

Hence, the correct answer is option C.

6 0
2 years ago
Which of the following is a limited resource, which can take longer to be replenished than it takes to be used up?
Zarrin [17]
What is the list of choices?
8 0
2 years ago
Read 2 more answers
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