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3 years ago

How does a generator produce electrical energy?

Physics

2 answers:

Grace [21]3 years ago

8 0

Option b is the correct answer

Daniel [21]3 years ago

3 0

The correct answer is B. it converts mechanical energy to electrical energy.

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Two observers in different inertial reference frames moving relative to each other at nearly the speed of light see the same two

lions [1.4K]

Answer:

The correct answer is d Both the observer's are correct

Explanation:

We know by postulates of relativity that laws of physics are same in different inertial frames.

Thus for each of the frames they make observations related to their frames and since the observations are true for their individual frames they both are correct. But when we compare the two frames we need to use transformation equations to compare both the results.

3 0

3 years ago

How much of the Moon is always illuminated one time? Explain your answer.

Natalija [7]

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

6 0

3 years ago

A car is traveling at 7.0 m/s when the driver applies the brakes. The car moves 1.5 m before it comes to a complete stop. If the

viva [34]

Answer:

d. 6.0 m

Explanation:

Given;

initial velocity of the car, u = 7.0 m/s

distance traveled by the car, d = 1.5 m

Assuming the car to be decelerating at a constant rate when the brakes were applied;

v² = u² + 2(-a)s

v² = u² - 2as

where;

v is the final velocity of the car when it stops

0 = u² - 2as

2as = u²

a = u² / 2s

a = (7)² / (2 x 1.5)

a = 16.333 m/s

When the velocity is 14 m/s

v² = u² - 2as

0 = u² - 2as

2as = u²

s = u² / 2a

s = (14)² / (2 x 16.333)

s = 6.0 m

Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.

The correct option is d

4 0

3 years ago

A copper wire (density equal to 8900 kg / m3) 0.3 mm in diameter "floats" due to the force of the earth's magnetic field, which

Andrews [41]

Answer: $I=112.094\ A$

Explanation:

Given

density $\rho =8900\ kg/m^3$

diameter $d=0.3\ mm$

Magnetic field $B=5.5\times 10^{-5}\ T$

Force on the current carrying conductor placed in a magnetic field

$F=BIL\sin \theta$

where L=length of conductor

$\theta$ =angle between magnetic field and current

If the wire is floating then weight must be balanced by weight of wire

$Weight=mg=\rho ALg$

Therefore

$\rho ALg=BIL\times \sin 90$

$8900\times \frac{\pi}{4}(0.3\times 10^{-3})^2L\times 9.8=5.5\times 10^{-5}\times I\times L$

$I=\frac{8900\times \pi\times 9\times 10^{-8}\times 9.8}{4\times 5.5\times 10^{-5}}$

$I=112.094\ A$

5 0

3 years ago

A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a

aliya0001 [1]

Answer:

$P_2 = -1.9 \times 10^8 Pa$

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

$Q = A_1v_1 = A_2v_2$

at the upper end the area is given as

$A_1 = \pi r_1^2$

$A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2$

Also at the other end

$A_2 = \pi r_2^2$

$A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2$

now the speed at two ends is given as

$v_1 = \frac{20}{1.26 \times 10^{-3}}$

$v_1 = 159.15 m/s$

$v_2 = \frac{20}{0.314 \times 10^{-3}}$

$v_2 = 637 m/s$

now by Bernoulli's theorem we have

$P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2$

now we have

$0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0$

Now we have

$P_2 = -1.9 \times 10^8 Pa$

4 0

3 years ago