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Dafna1 [17]
2 years ago
6

A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t

akes up doubles. Day 1 has a certain amount, day 2 it is 2x that amount. It takes 87 days for the entire lake to be overrun by this new algae. How many days does it take to cover half of the lake? Show your work and explain your thinking. In science we need to be able to justify our answers.
hint: It is not the "obvious" answer.
Chemistry
1 answer:
FrozenT [24]2 years ago
4 0

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

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Svet_ta [14]

Answer:

2.40 M

Explanation:

The molarity of a solution tells you how many moles of solute you get per liter of solution.

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unit conversion



280.0

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

1 mole NaCl

58.44

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=

0.004791 moles NaCl

This means that the molarity of the solution will be

c

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6 0
3 years ago
12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1
uranmaximum [27]

Answer:

Wavelength, \lambda=3.3\times 10^{-18}\ m

Explanation:

We have,

Velocity of the object, v=5\times 10^5\ m/s

Mass of the object, m=4\times 10^{-22}\ kg

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m

So, the wavelength of the object is 3.3\times 10^{-18}\ m.      

5 0
3 years ago
A gas occupies 5.31 liters at a pressure of 0.55 atm. Determine the volume at standard pressure.
yuradex [85]

Answer:

Option A; V =  2.92 L

Explanation:

If we assume a lot of things, like:

The gas is an ideal gas.

The temperature is constant.

The gas does not interchange mass with the environment.

Then we have the relation:

P*V = n*R*T = constant.

Where:

P = pressure

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We know that when P = 0.55 atm, the volume is 5.31 L

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(0.55 atm)*(5.31 L) = constant

Now, when the gas is at standard pressure ( P = 1 atm)

We still have the relation:

P*V = constant = (0.55 atm)*(5.31 L)

(1 atm)*V = (0.55 atm)*(5.31 L)

Now we only need to solve this for V.

V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L

V = 2.92 L

Then the correct option is A.

7 0
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Nimfa-mama [501]

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A + B = AB
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<h3>What is an equilibrium constant?</h3>

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The equilibrium constant expression is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants.

If the value of K is greater than 1, the products in the reaction are favoured. If the value of K is less than 1, the reactants in the reaction are favoured.

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