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ddd [48]
3 years ago
14

Solve for the variable: 3(q-5)=2(q+5)

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0
Distribute
a(b+c)=ab+ac or
a(b-c)=ab-ac

so

3(q-5)=3q-15
2(q+5)=2q+10

3q-15=2q+10
minus 2q from both sides
q-15=10
add 15 to both sides
q=25
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Step-by-step explanation:

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Shelly wanted to buy a shirt for $25 and a skirt for $20.When she got to the check out stand, they added 8% tax to her total. Ab
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3 years ago
The park and movie theater are 3.4 inches apart on a map. If the map has a scale of 0.25 inch = 5 miles, find the actual distanc
lianna [129]

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

Step-by-step explanation:

The given is,

             Park and movie theater are 3.4 inches apart

             Map has a scale of 0.25 inch = 5 miles

Step:1

            Formula to calculate the number of scales for distance between park and theater,

                                        = \frac{Distance in map}{Scale value of map}

                                        = \frac{3.4}{0.25}

                                        = 13.6

            number of scales for distance between park and theater  = 13.6

Step:2

            Formula to convert distance inches to miles

                                      = Number of scale × Equivalent value inches to miles

                                      = 13.6 × 5

                                      = 68

            Actual distance between park and theater = 68 miles

Result:

           The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

6 0
4 years ago
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