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raketka [301]
3 years ago
9

Round 2 tens and 4.1 to the nearest one

Mathematics
1 answer:
Vesna [10]3 years ago
7 0
2=1
4.1=4
hope this helps u
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Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
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\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
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At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
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and so on.
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