If sin y° = a divided by 6. and tan y° = a divided by b., what is the value of cos y°?

Mathematics

1 answer:

eimsori [14]2 years ago

6 0

Answer:

cos y degrees = b/6

Step-by-step explanation:

sin = opposite side of triangle / hypotenuse

tan = opposite side of triangle / adjacent side of triangle

cos = adjacent side of triangle / hypotenuse

opposite side = a

adjacent side = b

hypotenuse = 6

cos y degrees = b/6

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PolarNik [594]

Answer:

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Step-by-step explanation:

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Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

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Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

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We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$