Answer:
35,000,000,000 mL
Explanation:
You first multiply 35 times 1000.
35,000 L
Now you multiply 35,000 times 10^6
35,000,000,000 mL
Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
Answer:
168.56 mL
Explanation:
density = mass/volume, use basic algebra skills to replace the volume and solve
CH₄ + 2O₂ → CO₂ + 2H₂O
From the equation, we know that methane and carbon dioxide have the same number of moles.
no. of moles of CO₂ produced = no. of moles of methane
= 4.5 × 10⁻³ ÷ (12 + 1×4)
= 2.8125 × 10⁻⁴
∴ mass of CO₂ = 2.8125 × 10⁻⁴ × (12 + 16×2)
= 12.375 × 10⁻³ g
Because the speed of light is determined by the medium that is it in. If light is in a vacuum it goes 300 million meters per second but it is slower in air, and even slower in water because water is more dense than the previous two.
