How many grams of Ca(OH)2 are needed to produce 500 mL of 2.99 M Ca(OH)2 solution? 1L=1000mL
1 answer:
Answer:
74 g/mol
Explanation:
Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol
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Answer:
Oxidation number:
3*1+ oxidation number of J+2*-2= -1
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