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Leona [35]
2 years ago
13

How many grams of Ca(OH)2 are needed to produce 500 mL of 2.99 M Ca(OH)2 solution? 1L=1000mL

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

74 g/mol

Explanation:

Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol

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What is the wavelength, in nm, of radiation which has an energy if 3.371 x 10^-19 joules per photon?
mr_godi [17]

Answer:

The correct option is:

D) 589.3 nm

Explanation:

Energy of one photon = 3.371\times10^{-19}J

Energy=\frac{hc}{\lambda}\\\\h=Planck's\:constant=6.626\times10^{-34}J/s\\c=speed\:of\:light=3\times10^{8}m/s\\\lambda=wavelength\:of\:radiation\\\\\lambda=\frac{hc}{Energy}=\frac{6.626\times10^{-34}\times3\times10^{8}}{3.371\times10^{-19}}=5.897\times10^{-7}m=589.7nm\\

Hence, the wavelength (in nm) of radiation is 589.7nm (approximately equal to 589.3nm)

5 0
3 years ago
What is the density of a bar of soap with a mass of 715g, and a volume of 866cm3?
mihalych1998 [28]

Answer:

0.826 g/cm³

Explanation:

density = mass/volume

density = 715 g/866 cm³

density = 0.82564 g/cm³

Rounded to 3 significant figures: 0.826 g/cm³

4 0
2 years ago
There is a mixture of three gases. We know the total pressure is 2.50 atmosphere and the pressure of the oxygen and the nitrogen
Viktor [21]

Answer:

1.14 atm and 1.139 mol

Explanation:

The <em>total pressure</em> of the container is equal to the <u>sum of the partial pressure of the three gasses</u>:

  • P = Poxygen + Pnitrogen + Pcarbon dioxide
  • 2.50 atm = 0.52 + 0.84 + Pcarbon dioxide

Now we <u>solve for the pressure of carbon dioxide</u>:

  • Pcarbon dioxide = 1.14 atm

To c<u>alculate the number of CO₂ moles </u>we use <em>PV=nRT</em>:

  • P = 1.14 atm
  • V = 25.0 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 32 °C ⇒ 32 + 273.16 = 305.16 K

1.14 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305.16 K

  • n = 1.139 mol
5 0
3 years ago
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately to 4 significant fi
zmey [24]

Answer:

Average density for method A = 2.4 g/cm³

Average density for method B = 2.605 g/cm³

Explanation:

In order to calculate the average density for each method, we need to add the data for each method, and then divide the result by the number of measurements (in this case is 4 for both methods):

  • For Method A:

Σ = 2.2 + 2.3 + 2.7 + 2.4 = 9.6

Average = 9.6/4 = 2.4 g/cm³

  • For Method B:

Σ = 2.603 + 2.601 + 2.605 + 2.611 = 10.420

Average = 10.420/4 = 2.605 g/cm³

5 0
3 years ago
Suppose we have 100 g of each of the following substances. Which sample contain the greatest number of moles (F.W. = Formula Wei
Sindrei [870]

Answer:

100 g of water has the highest number of moles

Explanation:

Recall that the number of moles is obtained as given mass/formula weight

For HCl;

number of moles = 100g/36.5g/mol = 2.7 moles

For H2O;

number of moles = 100g/18g/mol = 5.5 moles

For MgCO3

number of moles = 100g/84.3 g/mol = 1.2 moles

For AlCl3

number of moles = 100g/133.3g/mol = 0.75 moles

For NaCl

number of moles = 100g/58.4 g/mol = 1.7 moles

3 0
3 years ago
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