Answer:
An excellent experiment is to heat sodium thiosulfate in a water bath. The solid crystals will dissolve into the water in the hydrated crystals forming a supersaturated solution. ... Placing a small crystal in the supersaturated solution will cause the liquid to turn solid.
Answer:
Yes.
Explanation:
Yes, this difference of readings will definitely affect the results of the experiment as well as the E values because the readings taken by both students are different from one another. There is a fault in one of the thermometer because both shows different readings of temperature of the same solution. This will affect the overall experiment and due to this error, we are unable to tell that which one reading is correct so the answer is uncertain or unsure.
Answer:
See the attached image
Explanation:
The first step is the production of the <u>carboanion</u> in the 
compound. We will get the <u>negative charge</u> on the methyl group and the <u>positive charge</u> in the Li atom.
Then the carboanion can <u>attack the acetone</u>. The double bond of the oxo group would <u>delocalized</u> upon the oxygen, generating a positive charge in the carbon that can be attacked by the carboanion formaiting a <u>new C-C bond</u>.
The answer is b
Explanation:
Answer:
OPTION C) All hydrogen ions and all hydroxide ions have reacted to produce water, and so neither ion remains free in solution.
Explanation:
The PH reading on the left axis of the graph shows a value of 7.
A value of 7 on the PH scale implies that equal number of hydrogen ions completely reacted with hydroxyl ions to produce water i.e there is no excess of hydrogen and hydroxyl ion remaining in solution.
For values greater than 7, a basic solution is formed and it signifies the presence of excess hydroxyl ion. If the value is less than 7, there is more hydrogen ions in the solution formed and it is said to be acidic.
At point 7, the hydrogen and hydroxyl ions are equal and completely neutralize out one another.
Note: The acid solution would require a base volume of 20mL to be completely neutralized according to the plot. If it is less, the PH shifts to the left and the solution becomes acidic. If it more, the solution becomes basic and the PH shifts rightwards.
