Question

Complete the Lewis structure of the molecule. Draw the missing dots and dashes representing the valence electrons in the molecule. PLEASE HELP ME!!!!!!!!

Answer 1

Answer :  The Lewis structure of $S_2O_2$ is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $S_2O_2$

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $S_2O_2$ = 2(6) + 2(6) = 24

According to Lewis-dot structure, there are 10 number of bonding electrons and 14 number of non-bonding electrons.

Answer 2

Answer:

Explanation:

Look on the periodic table. Look for oxygen, O, and sulfur, S. What group are they in? They are both in group 16. So...you would put 6 dots around all 4 elements.

Then distribute the valence electrons to each other until they are all balanced. A balanced element will have 8 valence electrons. Don't forget, if you don't have enough elements to make every element balanced, add more.