Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,






Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,

Now, 






Score puts someone in the 90th percentile is 638.
Answer:
Solution (-2, 7)
Step-by-step explanation:
2x + 3y = 17 (1)
5x + 6y = 32 (2)
Using elimination method
Multiply (-2) to the equation (1)
-4x - 6y = -34
Now you have 2 new equations
-4x - 6y = -34
5x + 6y = 32
----------------------------Add
x = -2
Substitute x = -2 into 2x + 3y = 17
2(-2) + 3y = 17
- 4 + 3y = 17
3y = 21
y = 7
Solution (-2, 7)
It’s not hard bro you gotta lean probability it’s really easy
9514 1404 393
Answer:
Step-by-step explanation:
These "special" right triangles have side length ratios that it is useful to remember.
<u>45°-45°-90° triangle</u>
Sides have the ratios 1 : 1 : √2. That is, x is √2 times as long as the side length shown as 18.
x = 18√2
<u>30°-60°-90° triangle</u>
Shortest to longest, sides have the ratios ...
1 : √3 : 2
That is, y is √3 times the length of the side marked 18, and z is 2 times the length of the side marked 18.
y = 18√3
z = 2·18 = 36
Answer:
-35a
Step-by-step explanation:
Here, you just distribute: -7 * 5a
= -35a