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Damm [24]
3 years ago
7

Determine the center and radius of the following circle equation:

Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Answer:

x^2-18x+y^2+18y+137=0

express both x and y term in completed square form

(x-9)^2 -81+(y+9)^2-81+137=0

(x-9)^2+(y+9)^2-25=0

(x-9)^2+(y+9)^2=5^2

here the x coordinate of the centre is +9

y coordinate is -9(the negative value of the value associated with the x and y square brackets)

radius=5

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CLICK HERE IF YOU HAVE BIG FEET <br><br> Using the function g( x) = -2 x – 11, calculate g(-3).
Leokris [45]

════════ ∘◦❁◦∘ ════════

<h3>Answer = -5</h3>

════════════════════

<h3>Known</h3>

g(x) = -2x - 11

════════════════════

<h3>Question</h3>

g(-3) = ..?

════════════════════

<h3>Way to do</h3>

#since x inside (x) change into (-3) then it means that you only need to change x into -3

g(-3) = -2(-3) - 11

g(-3) = 6 - 11

g(-3) = -5

════════════════════

6 0
3 years ago
1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang
Mandarinka [93]
1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is \frac{ \sqrt{3} }{2} a

2. if a a=25 ft, then the height is \frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7 (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}

so the total area of the roof is \frac{ \sqrt{3} }{2} a^{2} +3al

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al


5. so the area now is \frac{ \sqrt{3} }{2} a^{2} +2al

6. now a=25 and l=2a=50

Area=\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2}  (\frac{ \sqrt{3} }{2} +4)=625*4.866

=3041.3 (ft squared)

7 0
4 years ago
Read 2 more answers
8hiobhjgjgjvygvm,dfndfjkgnvabjchdbsnfbhj
Pavlova-9 [17]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Likeee i need help please man please
11Alexandr11 [23.1K]

Answer: this is so easy you got this

Step-by-step explanation:

YOU WILL NEVER SUCCEED IF YOU DON’T TRY

search it up if you really need help

3 0
3 years ago
Which of these sequences is a geometric sequence?
____ [38]

Answer:

if we take ratio then answer is option D

8 0
3 years ago
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