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oee [108]
3 years ago
15

How do we solve this??

Mathematics
2 answers:
jasenka [17]3 years ago
4 0

Answer:

Y= 42

Step-by-step explanation:

The answer would be 42 because if x=9 and the equation is 5x you have to multiply and that will give you 45 and then subtract 3 which would give you  42

Svetllana [295]3 years ago
4 0
Y=42 (you can also use Photomath for these kind of problems) hope I helped:))
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Noah is ordering a taxi from an online taxi service. The taxi charges $2.50 just for the pickup and then an additional $2 per mi
d1i1m1o1n [39]

Answer:

$10.50

Step-by-step explanation:

We can make an equation

2.50+2x=?

x=4 because we are riding 4 miles.

so it's 2.5+2*4=?

let's solve

2.5+8=$10.50

8 0
3 years ago
A video game club charges a fixed annual membership fee of $20 and $2 per video game rented. Let f(n) represent the total annual
Rasek [7]
<span>fixed annual membership fee of $20
</span><span>$2 per video game rented.
</span><span>Let f(n) represent the total annual cost of renting n video games
so
f(n) = 20 + 2n

if </span><span>increased by $15 the next year
then
f(n) = </span>20 + 2n + 15
f(n) = 2n + 35

answer
<span>f(n) = 2n + 35 (first choice)</span>
5 0
3 years ago
The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
Please say what the answer is and show the steps
kolbaska11 [484]
This doesn’t make any sense
6 0
2 years ago
Read 2 more answers
Round 7.954 to the place named
Andrej [43]
What is it rounded too?
4 0
3 years ago
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