Answer:
multiplication by d=> 2d^3, 11d^2, -4d
multiplication by -9=>-18d^2,-99d, 36
The answers are in order from left to right.
Step-by-step explanation:
mark me as brainliest plz
Answer:
1
Step-by-step explanation:
Note there is a common ratio between consecutive terms, that is
10 ÷ 20 = 5 ÷ 10 = 2 ÷ 5 =
Thus to obtain the next term in the sequence multiply the previous term by
2 × = 1
Answer:
y = 3x -5
Explanation:
Since it's parallel, it will have the same slope: 3.
So you'll have y = 3x + a, and we need to find a.
Plug in the values for the point we are given:
7 = 3(4) + a
7 = 12 + a
a = -5
<h3>So there you have it: y = 3x - 5</h3>
Answer:
3.74
Step-by-step explanation:
First, we can place the square root of fourteen between it's two closest square roots:
√9 < √14 < 16
3 < √14 < 4
Now since 14 is closer to 16 than 9, we can do this:
3.9^2 = 15.21
3.8^2 = 14.44
3.7^2 = 13.69
We can see that √14 must be between 13.69, and 14.44, which are 3.7^2 and 3.8^2, so we know that √14 must be between those numbers. If we go even further, then:
3.72^2 = 13.83
3.73^2 = 13.91
3.74^2 = 13.98
3.75^2 = 14.06
We can see that 3.74^2 is the closest to 14, only .02 away from the actual number, so 3.74 is our estimate for the square root of fourteen.
Brainliest?
<span>6.5 x 10^6
To answer this question, you need to divide the mass of the sun by the mass of mercury. So
2.13525 x 10^30 / 3.285 x 10^23 = ?
To do the division, divide the mantissas in the normal fashion
2.13525 / 3.285 = 0.65
And subtract the exponents.
30 - 23 = 7
So you get
0.65 x 10^7
Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving
6.5 x 10^6
So the sun is 6.5 x 10^6 times as massive as mercury.</span>