A random variable following a binomial distribution over trials with success probability has PMF
Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.
The mean is given by the expected value of the distribution,
The remaining sum has a summand which is the PMF of yet another binomial distribution with trials and the same success probability, so the sum is 1 and you're left with
You can similarly derive the variance by computing , but I'll leave that as an exercise for you. You would find that , so the variance here would be
The standard deviation is just the square root of the variance, which is
You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:
Divide both sides by 2. (p) ÷ 2 = (2w + 2l) ÷ 2
Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself). p/2 - l = w
You replace w with the equation above p/2 - l = w
Multiply out the L.
Plug in all your numbers a = 110 and p = 42
Move everything to the left side so would be positive (makes the equation easier when is positive).
Factor.
Make each parenthesis set equal to 0.
Add.
By doing this you solve for both the width and length so the answer is: w = 11 L = 10