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What multiplicities are observed for the signals in the off-resonance decoupled 13c nmr spectrum of (2e)-3-chloro acrylaldehyde?

Flauer [41]

The multiplicities that are observed for the signals in the off-resonance decoupled 13c nmr spectrum of (2e)-3-chloro acrylaldehyde is a singlet, a triplet, and a quartet. The correct option is E.

<h3>What is off-resonance decoupling?</h3>

Off-resonance decoupling is a process of removing all hydrogen and carbon coupling from a signal except for the place which is near the nucleus or joined with the nucleus.

In NMR also, the coupling of hydrogen and carbon is removed except for the place near the nucleus.

Thus, the correct option is E) a singlet, a triplet, and a quartet.

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The question is incomplete. Your most probably complete question is given below:

A) 2 singlets and a doublet

B) a singlet and 2 doublets

C) 3 singlets

D) a singlet, a doublet, and a triplet

E) a singlet, a triplet, and a quartet

8 0

2 years ago

Which representation of a hydrogen molecule is not correct?

USPshnik [31]

Hydrogen is the element with atomic number one. The representation of the hydrogen molecule with a double bond is incorrect.

<h3>What is a double bond?</h3>

A double bond is a type of chemical bond that involves two pairs or four bonding electrons of the atom in a molecule. They are stronger and shorter bonds compared to single bonds.

A hydrogen molecule can never have a double bond in its molecule as it has only a single electron in its shell and cannot form a double bond due to the lack of four electrons.

Therefore, hydrogen molecules cannot form a double bond.

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3 0

2 years ago

How many neutrons does the following nuclide have? 253/100 Fm A. 253 B. 100 C. 153 D. none of these

lara [203]

I believe the correct answer is C. The number of neutrons in the <span>253/100 Fm would be 153. The numbers beside Fm are used to determine this. Two hundred fifty three represents the mass number which is the sum of protons and neutrons in the nuclide while 100 represents the atomic number which is the number of protons. Therefore,

253 = neutrons + 100
neutrons = 153</span>

3 0

3 years ago

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Express the following in standard exponential format <br> 3,186

Colt1911 [192]

3.19 x 10³

Explanation:

The exponential format of the a figure is used to simplify the expression of big numbers to make them easier to work with.

The number is simply raised to the power of tens.

3,186

This is number three thousand one hundred and eighty six

The highest number here is a thousand

A thousand is 10³

So we simply take the rest of the values and express it this way;

3.186 x 10³ or 3.19 x 10³ on rounding up

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3 0

3 years ago

The heat of combustion of propane, C3H8 (g) is -2057 kJ/mol. What would be the enthalpy change if enough propane was burned to g

Digiron [165]

Considering the reaction stoichiometry, the enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

The balanced reaction is:

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l)

The heat of combustion of propane, C₃H₈, is -2057 kJ/mol. This is, 2057 kJ is released for every 1 mol C₃H<u>₈</u>.

So to determine the enthalpy change if enough propane was burned to emit 12 moles of carbon dioxide, you must take into account the stoichiometry of the reaction.

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Then you can apply the following rule of three: if by stoichiometry 3 moles of CO₂ are produced by 1 mole of C₃H₈, 12 moles of CO₂ are produced by how many moles of C₃H₈?

$amount of moles of C_{3} H_{8} =\frac{12 moles of CO_{2}x1 mole of C_{3} H_{8} }{3 moles of CO_{2}}$

<u><em>amount of moles of C₃H₈= 4 moles</em></u>

So to determine the enthalpy change, you can apply the following rule of three: If for each mole of C₃H₈ 2057 kJ are released, for 4 moles of C₃H₈ how much heat is released?

$Heat released=\frac{4 molesx2057 kJ}{1 mole}$

<u><em>Heat released= 8228 kJ</em></u>

The enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

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5 0

3 years ago