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muminat
4 years ago
11

in the process of electricity, what flows through the wires?A) protons B)neutronsC)electronsD)positrons

Chemistry
1 answer:
gizmo_the_mogwai [7]4 years ago
8 0

Electrons is your answer

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3. Calculate the average atomic mass for the sample of atoms shown below.
murzikaleks [220]

Answer:B:63.75

Explanation:(5/8 x 63)+(3/8 x 65)=(0.625 x 63)+(0.375 x 65)=63.75

8 0
4 years ago
50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol
Viefleur [7K]

Answer:

Approximately 0.47\; \rm mol \cdot L^{-1} (note that 1\; \rm M = 1 \; \rm mol \cdot L^{-1}.)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this \rm NaNO_3 solution in water,

Let n be the number of moles of the solute in the whole solution. Let V represent the volume of that solution. The formula for the molarity c of that solution is:

\displaystyle c = \frac{n}{V}.

In this question, the volume of the solution is known to be 1250\; \rm mL. That's 1.250\; \rm L in standard units. What needs to be found is n, the number of moles of \rm NaNO_3 in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of \rm NaNO_3 is 85\; \rm g \cdot mol^{-1} means that the mass of one mole of

\displaystyle n = \frac{m}{M}.

For this question,

\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}.

Calculate the molarity of this solution:

\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}.

Note that 1\; \rm mol \cdot L^{-1} (one mole per liter solution) is the same as 1\; \rm M.

8 0
3 years ago
Can you light a diamond on fire
miss Akunina [59]

Answer:

Yes, diamond can be burned. The most common form of burning in everyday life is carbon combustion. In carbon combustion, carbon atoms break their bonds with each other and with other atoms (which requires energy) to form bonds with oxygen atoms (which releases even more energy than first required). The net extra energy released in this reaction can then go on to rip more carbon atoms free of their non-oxygen neighbors, thus continuing the reaction, or the energy can escape as heat and ligh

Explanation:

7 0
3 years ago
How many atoms of K are present in 195.49 grams of K? 3.0110 × 1024 6.0220 × 1024 1.1772 × 1026 4.5797 × 1027
Ierofanga [76]
<h2>Hello!</h2>

The answer is: 3.0110x10^{24}

<h2>Why?</h2>

First, we need to look for the K molecular mass:

K=39,098 g/mol

Also, we need to remember that 1 mol of a compound or element is equal to 6,022x10^{23} of that compound.

From the statement, we are asked to calculate how many atoms of K are present in 195,49 of K.

So, doing the calculations, we have:

195,49g*\frac{1mol}{39,08}*\frac{6,022x10^{23} atoms}{1 mol K} =3,0110x10^{24} \\

So, we have 3.0110x10^{24} atoms of K in 195,49 grams of K.

Have a nice day!

3 0
3 years ago
Check all the answers that apply. Energy is the ability to
Juliette [100K]
Answer:

All the above.

Explanation:

Energy is defined as the ability to do work. And changes in every occur in all changes of matter. Energy is neither created nor destroyed in these changes, but simply changes from on form to another.
4 0
3 years ago
Read 2 more answers
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