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Mademuasel [1]
3 years ago
8

PLEASE ANSWER + BRAINLIEST!!!!

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
The answer is D because it does not end up passing through another point. You can discover this by using the vertical line test.
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The length of the rectangle is 4cm less than its width . what are the dimensions of the rectangle if its area is 140
melomori [17]
Let the width of the rectangle be x
Then length =x-4
Area=x(x-4)=140
x²-4x=140
x²-4x-140=0
x²-14x+10x-140=0
x(x-14)+10(x-14)=0
(x-14)(x+10)=0
Therefore,length=14 cm and  width=10 cm

8 0
3 years ago
16 - 2z-4/3 when z=18
Colt1911 [192]

Answer:

z= -3

Step-by-step explanation

5 0
3 years ago
One number is five less than a second number. Five times the first is 15 more than 6 times the second. Find the numbers
Shalnov [3]

Answer:

x = -45, y = -40

Step-by-step explanation:

Based on the first clue, we find out that

x + 5 = y

5x = 6y + 15

We can re-write the first equation to x = y - 5.

Therefore, the second equation can also be written as 5(y - 5) = 6y + 15

This can be simplified to 5y - 25 = 6y + 15

We can subtract 6y from each side, and add 25 to each side;

5y - 6y = 15 + 25

Therefore, -y = 40

Therefore y = -40.

Now let's plug this back into the original equation, to get : x  + 5 = -40

x=-45

4 0
3 years ago
Plot the point (4, −3). Start at the origin. Move 4 units . Move 3 units . The point is at .
Naily [24]

Answer:

the point is D

Step-by-step explanation:

brainliest plz

7 0
2 years ago
Read 2 more answers
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
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