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3 years ago

10

Joe spends $8 on lunch and $6.50 on dry cleaning. He also buys 2 shirts that cost the same amount. Joe spends a total of $52. Wh

at is the cost of each shirt?

1 answer:

erica [24]3 years ago

4 0

Each shirt cost $18.75

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The angle of elevation of the sun is 68° when a tree casts a shadow 14.3 m long. How tall is the tree, to the nearest tenth of a

Igoryamba

See the attached picture to better understand the problem

we know that
in the right triangle ABC
tan 68°=opposite side angle 68/adjacent side angle 68
opposite side angle 68=AB----- height of the tree
adjacent side angle 68=BC-----> 14.3 m
so
tan 68=AB/BC-----> solve for AB
AB=BC*tan 68-----> AB=14.3*tan 68------> AB=35.39 m------> AB=35.4 m

the answer is
the height of the tree is 35.4 m

7 0

3 years ago

Martha is buying hot dogs and buns for the

pychu [463]

Answer:

6 packages of hot dogs

5 packages of buns

Step-by-step explanation:

The least common multiple of 10 and 12 is 60.

Divide 60 by the amount of product in each package to find the answers.

Hope this helps ^-^

5 0

4 years ago

Read 2 more answers

Write -5 4/5 as a decimal<br> -5 4/5=?

dybincka [34]

Answer:

The answer is 5.8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

BRAINIEST TO CORRECT ANSWER<br> (2x^2 +7x)+ (−x^2+10x+3)

Finger [1]

Answer: x2+17x+3

Step-by-step explanation:

2x2+7x−x2+10x+3

=2x2+7x+−x2+10x+3

Combine Like Terms:

=2x2+7x+−x2+10x+3

=(2x2+−x2)+(7x+10x)+(3)

=x2+17x+3

6 0

3 years ago

There are two cameras that take pictures of a traffic intersection. Camera A starts taking pictures at 6 AM and takes a picture

Scilla [17]

Answer:

41 minutes before noon

Step-by-step explanation:

The given parameters are;

The time camera A starts taking pictures = 6 AM

The frequency of picture taking by camera A = Once every 11 minutes

The time camera B starts taking pictures = 7 AM

The frequency of picture taking by camera B = Once every 7 minutes

The number of times both cameras take a picture at the same time before noon = 4 times

Let the time the two cameras first take a picture the same time be x, we have;

11·y - 60 = x

7·z = x

Taking the number of times after 7 camera A snaps and noting that the first snap is 6 minutes after 7, we have

11·b + 6 = x

7·z = x

x is a factor of 7 and 11·b + 6 and x is some minutes after 7

By using Excel, to create a series of values for Camera A based, on 11·b + 6, and dividing the results by 7 we have the factors of 7 at;

28, 105, 182, and 259 minutes after 7

Given that there are 60 minutes in one hour, we have;

259/60 = 4 hours 19 minutes, which is 11:19 a.m. or 41 minutes before noon.

4 0

3 years ago