There is a 3/5 or 60% probability that there will be 3 girls and a 2/5 or 40% probability that there will be boys
Answer:b
Step-by-step explanation: i thinks its b
Simplifying
(6x + -5) + -1(7x + 2) = 0
Reorder the terms:
(-5 + 6x) + -1(7x + 2) = 0
Remove parenthesis around (-5 + 6x)
-5 + 6x + -1(7x + 2) = 0
Reorder the terms:
-5 + 6x + -1(2 + 7x) = 0
-5 + 6x + (2 * -1 + 7x * -1) = 0
-5 + 6x + (-2 + -7x) = 0
Reorder the terms:
-5 + -2 + 6x + -7x = 0
Combine like terms: -5 + -2 = -7
-7 + 6x + -7x = 0
Combine like terms: 6x + -7x = -1x
-7 + -1x = 0
Solving
-7 + -1x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '7' to each side of the equation.
-7 + 7 + -1x = 0 + 7
Combine like terms: -7 + 7 = 0
0 + -1x = 0 + 7
-1x = 0 + 7
Combine like terms: 0 + 7 = 7
-1x = 7
Divide each side by '-1'.
x = -7
Simplifying
x = -7
Answer:
The standard form of a quadratic equation is ax2+bx+c=0, where a,b and c are real numbers and a≠0.
Answer:
I hope this helps :D
Step-by-step explanation:
4
It can be done a lot easier: instead of calculating the probability of one head, two heads, three heads, ... one just needs to calculate the probability of no heads: that is simply 0.5
0.5
n
. If you subtract it from 1, you get the probability you want: it's because that's the chance of not no heads, meaning at least one head. So, the formula is: 1−0.5
1
−
0.5
n
More formally: if X is throwing at least one head,
()=1−(¬)
P
(
X
)
=
1
−
P
(
¬
X
)
, where ¬
¬
X
is throwing zero heads.
