1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrei [34K]
3 years ago
6

g Which ONE of the following pure substances will exhibit hydrogen bonding? A) methyl fluoride, FCH3 B) dimethyl ether, CH3C–O–C

H3 C) formaldehyde, H2C=O D) trimethylamine, N(CH3)3 E) hydrazine, H2N-NH2
Chemistry
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

C) formaldehyde, H2C=O.

Explanation:

Hello,

In this case, given that the hydrogen bondings are known as partial intermolecular interactions between a lone pair on an electron rich donor atom, particularly oxygen, and the antibonding molecular orbital of a bond between hydrogen and a more electronegative atom or group. Thus, among the options, C) formaldehyde, H2C=O, will exhibit hydrogen bonding since the lone pair of electrons of the oxygen at the carbonyl group, are able to interact with hydrogen (in the form of water).

Best regards.

You might be interested in
Calculate the concentration of OH-in a solution that has a concentration of H+ = 8.1 x 10^−6 M at 25°C. Multiply the answer you
Nat2105 [25]

Answer:

The answer is 12.35

Explanation:

From the question we are given that the concentration of H^{+} is 8.1 * 18^{-6}M

 Generally The rate equation is given as

                                                           K_{w} = [H^{+} ][OH^{-} ]

and K_{w} the rate constant has a value 1 * 10^{-14}

     Substituting and making [OH^{-}] the subject we have

                                                 [OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}

                                                  [OH ^ {-}] = 1.235 * 10^{-9}M

                            Multiply the value by 10^{10} as instructed from the question we have  

                       Answer =   1.235 * 10 ^{-9} * 10^{10} = 12.35

Hence the answer in 2 decimal places is 12.35

7 0
3 years ago
Help please, please,please. ....​
Vaselesa [24]

Answer:

the answer is nitrogen

Explanation:

u can right this for explain your answer-

( nitrogen is unreactive

nitrogen doesn't support burning )

orrrrr

(contains no oxygen

all the other jars contain oxygen)

3 0
3 years ago
As part of an investigation, students combined substances in a beaker to observe
aleksklad [387]

Answer:

please mark brainlest and it's  Procedure 1: One of the products was a gas that escaped into the air.

Procedure 2: A gas from the air reacted with one of the other reactants

Explanation:

the gas ca evaporate so it would'nt be a or c and b dosent make sense.

3 0
3 years ago
Methane undergoes combustion. Which products form?
Aleksandr [31]

<u>M</u><u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>e</u><u> </u>is a carbon compound which undergoes combustion to <em><u>release energy</u></em> and form bi production which are <u>Carbon</u><u> </u><u>dioxide</u><u> </u>( CO2 )<u> </u><u>and</u><u> </u> <u>W</u><u>ater</u> ( H20 ).

the balanced chemical equation for the reaction is : -

  • CH4 + 2 O2 =》CO2 + 2 H2O
3 0
3 years ago
The solubility of glucose at 30°C is
weqwewe [10]

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL \times \frac{0.996g}{1mL} =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O \times \frac{550gGlucose}{398gH_2O} = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

6 0
3 years ago
Other questions:
  • NEED HELP! FAST! WILL CHOOSE BRAINLIEST ANSWER!
    7·1 answer
  • 150 lb of NaCl are initially dissolved in 500 gal of a NaCl solution in a container. Water is continuously added to the containe
    12·1 answer
  • If elements in group 17 of the periodic table, what do they have the same of?
    15·1 answer
  • How is a pure substance different from a mixture?
    13·2 answers
  • The Sun appears to move in the sky because
    11·2 answers
  • Water droplets forming on a window on a cool day is an example of evaporation
    12·2 answers
  • 5. Which contains more nitrogen: 60g of urea, (NH2)2CO, or 100g of ammonium sulphate, (NH4)2SO4
    13·1 answer
  • Help plzzz Convert 6.1 ks to s.
    10·1 answer
  • What happens is the PH changes
    5·1 answer
  • Which refers specifically to a heated solution that holds more dissolved solution than it can hold at a lower temperature?.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!