Answer:
The answer is 12.35
Explanation:
From the question we are given that the concentration of
is
Generally The rate equation is given as
![K_{w} = [H^{+} ][OH^{-} ]](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%20%5BH%5E%7B%2B%7D%20%5D%5BOH%5E%7B-%7D%20%5D)
and
the rate constant has a value 
Substituting and making [
] the subject we have
![[OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%20%5D%20%3D%20%5Cfrac%7B1%20%2A%2010%5E%7B-14%7D%7D%7B%5BH%5E%7B%2B%7D%5D%7D%20%3D%20%5Cfrac%7B1%20%2A%2010%5E%7B-14%7D%7D%7B8.1%20%2A10%5E%7B-6%7D%7D%20%3D1.235%20%2A%2010%5E%7B-9%7D)
![[OH ^ {-}] = 1.235 * 10^{-9}M](https://tex.z-dn.net/?f=%5BOH%20%5E%20%7B-%7D%5D%20%3D%201.235%20%2A%2010%5E%7B-9%7DM)
Multiply the value by
as instructed from the question we have
Answer =
Hence the answer in 2 decimal places is 12.35
Answer:
the answer is nitrogen
Explanation:
u can right this for explain your answer-
( nitrogen is unreactive
nitrogen doesn't support burning )
orrrrr
(contains no oxygen
all the other jars contain oxygen)
Answer:
please mark brainlest and it's Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants
Explanation:
the gas ca evaporate so it would'nt be a or c and b dosent make sense.
<u>M</u><u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>e</u><u> </u>is a carbon compound which undergoes combustion to <em><u>release energy</u></em> and form bi production which are <u>Carbon</u><u> </u><u>dioxide</u><u> </u>( CO2 )<u> </u><u>and</u><u> </u> <u>W</u><u>ater</u> ( H20 ).
the balanced chemical equation for the reaction is : -
Answer:
Saturated solution
We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.
Explanation:
Step 1: Calculate the mass of water
The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

Step 2: Calculate the mass of glucose per 100 g of water
550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

Step 3: Classify the solution
The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.