Answer:
34.02 g.
Explanation:
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In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:
Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:
So probably, the gas may be H₂S.
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The concentration of solution in M or mol/L can be calculated using the following formula:
.... (1)
Here, n is number of moles and V is volume of solution in L.
The molecular formula of potassium sulfate is thus, there are 2 moles of potassium in 1 mol of potassium sulfate.
1 mol of potassium will be there in 0.5 mol of potassium sulfate.
Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.
Number of moles can be calculated as follows:
Here, m is mass and M is molar mass
Putting the values,
Thus, number of moles of will be .
The volume of solution is 225 mL, converting this into L,
Thus,
Putting the values in equation (1),
Therefore, concentration of potassium sulfate solution is 0.236 M.
Answer:
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Answer:
5.9x10^-2 M
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Concentration of CO, [CO] = 0.30 M
Concentration of H2, [H2] = 0.10 M
Concentration of H2O, [H2O] = 0.020 M
Equilibrium constant, K = 3.90
Concentration of CH4, [CH4] =..?
Step 2:
The balanced equation for the reaction. This is given below:
CO(g) + 3H2(g) <=> CH4(g) + H2O(g)
Step 3:
Determination of the concentration of CH4.
The expression for equilibrium constant of the above equation is given below:
K = [CH4] [H2O] / [CO] [H2]^3
3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3
Cross multiply to express in linear form
[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3
Divide both side by 0.02
[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02
[CH4] = 5.9x10^-2 M
Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M
Answer:
4.4×10² cm³
Explanation:
From the question given above, the following data were obtained:
Diameter (d) = 68.3 mm
Height (h) = 0.120 m
Volume (V) =?
Next, we shall convert the diameter (i.e 68.3 mm) to cm.
This can be obtained as follow:
10 mm = 1 cm
Therefore
68.3 mm = 68.3 mm / 10 mm × 1 cm
68.3 mm = 6.83 cm
Therefore, the diameter 68.3 mm is equivalent 6.83 cm.
Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:
1 m = 100 cm
Therefore,
0.120 m = 0.120 m/ 1 m × 100 cm
0.120 m = 12 cm
Therefore, the height 0.120 m is equivalent 12 cm.
Next, we shall determine the radius of the cylinder. This can be obtained as follow:
Radius (r) is simply half of a diameter i.e
Radius (r) = Diameter (d) /2
r = d/2
Diameter (d) = 6.83 cm
Radius (r) =?
r = d/2
r = 6.83/2
r = 3.415 cm
Finally, we shall determine the volume of the cylinder as follow:
Radius (r) = 3.415 cm
Height (h) = 12 cm
Volume (V) =?
Pi (π) = 3.14
V = πr²h
V = 3.14 × (3.415) ² × 12
V = 440 cm³
V = 4.4×10² cm³
Therefore, the volume of the cylinder is 4.4×10² cm³