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LenaWriter [7]
2 years ago
6

How many molecules of water are there in 10 lbs of water?

Chemistry
1 answer:
Scilla [17]2 years ago
3 0

55.556

Explanation:

or something like that

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Explain the neutralization of vitamin c with sodium hydrogen carbonate?
mars1129 [50]
Scientists have known the consequences of mixing sodium bicarbonate and vitamin C ever since 1936, when a study on the subject was published in the "Journal of Nutrition." The authors of this study measured the amount of vitamin C recovered from the urine of people who drank a fixed amount of orange juice. The authors determined that the amount of vitamin C excreted was decreased by administration of sodium bicarbonate. Followup studies in the 1940s showed that this effect was due to the neutralization of the vitamin C by the sodium bicarbonate.
3 0
3 years ago
Read 2 more answers
The reaction for producing glucose in plants, called photosynthesis, is:
Firlakuza [10]

Answer:

41.16 moles of H2O

Explanation:

Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.

Then, let's make a rule of three:

1 mol of glucose is produce by using 6 moles of water

6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O

8 0
3 years ago
Aluminum oxide reacts with hydrochloric acid to produce salt. What is the name of the salt produced?
KIM [24]

Answer:

IT IS CHLORIDE!

4 0
3 years ago
During which step of meiosis do the homologous chromosomes line up in the middle of the cell?
777dan777 [17]

Answer:

It is D

metaphase 1

Explanation:

in metaphase chromosome line up in the middle.

3 0
3 years ago
C5H12 + 8O2 → 5CO2 + 6H2O<br><br> Calculate the energy change for the reaction:
KATRIN_1 [288]
C5H12 (l) + 8O2 (g) ----> 5CO2 (g) + 6H2O (l)
Delta H = -3505.8 kJ/mol

C (s) + O2 (g) -----> CO2 (g)
Delta H = -393.5 kJ/mol

H2 (g) + (1/2)O2 (g) ------> H2O (l)
Delta H = -286 kJ/mol

Possible answers:
a. +35 kJ/mol
b. + 1,073 kJ/mol
c. -4,185 kJ/mol
d. -2,826 kJ/mol
e. -178 kJ/mol
8 0
3 years ago
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