How many molecules of water are there in 10 lbs of water?

Fresh water ___________, ________, and

EleoNora [17]

What is the full question?

4 0

3 years ago

Properties of calcium

MariettaO [177]

Hey there!

Your PHYSICAL properties of calcium is/are....

- COLOR which gives you a silvery whitish metallic color

- PHASE which is pretty much solid

- HARDNESS which is quite soft metal

- CRYSTALLINE STRUCTURES which is like a cubic symbol

- DUCTILITY which can be misused into millions of thin specs

- MALLEABILITY which forms the shape or vent

- MELTING POINT which is estimated to about 850 degree Celsius

- BOILING POINT which is estimated to 1,480 degree Celsius

The CHEMICAL properties of calcium is/are...

• CHEMICAL CODE

• OXIDATION which is used for the steel

• ISOTOPES calcium has about 6 of them

• COMPOUNDS includes marble and limestone (there’s more)

• FLAMMABILITY when it is burned into the air or in the oxygen it will most likely catch on fire

• REACTION TO WATER (H2O) it responds to the water fast in the beginning but slowly the reaction slows down due to the feeling of your calcium

• REACTION TO ACIDS it is exceedingly reactive

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0

4 years ago

Read 2 more answers

Automotive antifreeze consists of ethylene glycol, CH2(OH)CH2(OH), a nonvolatile nonelectrolyte. Calculate the boiling point and

spayn [35]

Answer:

Freezing point of solution = - 10.3°C

Boiling point of solution = 102.8°C

Explanation:

This is about colligative properties:

Freezing point depression → ΔT = Kf . m

ΔT = Freezing point of pure solvent - Freezing point of solution

Boiling point elevation → ΔT = Kb . m

ΔT = Boiling point of solution - Boiling point of pure solvent

Let's determine m which means molality (moles of solute in 1 kg of solvent)

Solute: Ethylene glycol → Mass = 25 g

Moles = Mass / Molar mass → 25 g / 60g/mol = 0.416 moles

Solvent: Water

25 % means, 25 g of solute in 100 g of solution

Therefore, the mass of water is 75 g (100 -25) . (Solution = Solute + Solvent)

We convert the mass from g to kg → 75 g . 1kg /1000g = 0.075 kg

Molality (mol/kg) = 0.416 m / 0.075kg = 5.55 m

We replace data in the formulas:

<u>Freezing point depression</u>:0° - Freezing point of solution= 1.86°C/m. 5.55 m

Freezing point of solution = - (1.86°C/m . 5.55m) = - 10.3°C

<u>Boiling point elevation</u>:Boiling point of solution - 100°C = 0.51°C /m . 5.55 m

Boiling point of solution = 0.51°C /m . 5.55 m + 100°C = 102.8°C

3 0

3 years ago

Help I don’t know what the answer is

irina [24]

Answer:-

10.0

Explanation: -

The equation is

N2O4 = 2NO2.

Concentration of NO2 = [NO2} = 0.500 M

Concentration of N2O4 = [N2O4] = 0.0250 M

Keq is the equilibrium constant.

It is the ratio of the concentration of products raised to the stoichiometric coefficient of the product to the concentration of the reactants raised to the stoichiometric coefficient of the reactants.

The expression for Keq = [NO2] ^2 / [N2O4]

= 0.500^2 / 0.0250

= 10.0

6 0

3 years ago

You need to make an aqueous solution of 0.139 M potassium phosphate for an experiment in lab, using a 250 mL volumetric flask. H

Crazy boy [7]

Answer:

7,38 g of K₃PO₄

Explanation:

Molarity is an unit of chemical concentration. 0,139 M means 0,139 moles of solute per liter of solution.

In this case, the solute is potassium phosphate (K₃PO₄; molar mass: 212,27 g/mol) and the volume of the solution must be 250mL≡0,25L.

Thus, the moles of potassium phosphate you need are:

0,139 mol/L×0,25L = 0,03475 moles of K₃PO₄

In grams:

0,03475 moles of K₃PO₄ × $\frac{212,27g}{1mol}$ = 7,38 g of K₃PO₄

I hope it helps!

7 0

4 years ago