Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V
Construction, like building a home/building, digging, like in a mine, and opening a soda can, where the part to open is a lever.
Answer:
H = 54.37
Explanation:
given,
lead ball attached at = 1.70 m
rate of revolution = 3 revolution/sec
height above the ground = 2 m
circumference of the circle = 2 π r
= 2 x π x 1.7
= 10.68 m
v = 32.04 m/s
using conservation of energy
H = 54.37
the maximum height reached by the ball is equal to H = 54.37
