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3 years ago

BRAINLEST HURRY PLZZ HELP the options for number 1 2 and 3 are A B C D

Physics

2 answers:

SCORPION-xisa [38]3 years ago

6 0

1. B
2.C
3.D
............

coldgirl [10]3 years ago

3 0

1.B
2.D
3.C
read at ur own risk

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5. How much heat is generated when an

Mila [183]

Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

pt=msΔT

2000×t=200×4200×60

t=25200

or t=25.2×103sec.

6 0

3 years ago

Can someone answer this question? {For me: question 48}

qaws [65]

0.000000218 = 2 x 10^ -8

4 0

3 years ago

If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring

Nastasia [14]

Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

7 0

3 years ago

The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge

lesya [120]

Answer:

Loss, $\Delta E=-10.63\ J$

Explanation:

Given that,

Mass of particle 1, $m_1=m =0.66\ kg$

Mass of particle 2, $m_2=7.4m =4.884\ kg$

Speed of particle 1, $v_1=2v_o=2\times 6=12\ m/s$

Speed of particle 2, $v_2=v_o=6\ m/s$

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

$m_1v_1+m_2v_2=(m_1+m_2)V$

$V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}$

$V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}$

V = 6.71 m/s

Initial kinetic energy before the collision,

$K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)$

$K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)$

$K_i=135.43\ J$

Final kinetic energy after the collision,

$K_f=\dfrac{1}{2}(m_1+m_2)V^2$

$K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2$

$K_f=124.80\ J$

Lost in kinetic energy,

$\Delta K=K_f-K_i$

$\Delta K=124.80-135.43$

$\Delta E=-10.63\ J$

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

7 0

3 years ago

Ahab has been sent to the shops by his mother. The shops are 1200 m from his

Iteru [2.4K]

Answer:

it will take him 200secs to run to the shops

(btw 200 seconds is 3minutes and 20secs)

Explanation:

distance = speed x time

time = distance / speed

1200 ÷ 6 = 200

time = 200seconds

hope this helps

brainliest please?

8 0

3 years ago