Find the magnitude of the sum
1 answer:
Answer:
8.57 m
Explanation:
To solve the problem, we have to decompose the two vectors along the two directions first:
Vector A:
- x component: Ax = +9.66 m
- y compoment: Ay = 0 (the vector lies along the x-axis)
Vector B:
- x component:
- y component:
So now we can find the sum of the two vectors by adding the components along each axis:
And the magnitude of the sum is given by Pythagorean theorem:
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Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.
where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing:
Answer:
The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.
Explanation:
For 2 quantities A and B represented as
and
The sum is represented as
For the the values given to us the sum is calculated as
Now the since the uncertainity inthe sum is
The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity
Thus closest distance equals meters