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Marianna [84]
3 years ago
9

Find the magnitude of the sum

Physics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

8.57 m

Explanation:

To solve the problem, we have to decompose the two vectors along the two directions first:

Vector A:

- x component: Ax = +9.66 m

- y compoment: Ay = 0 (the vector lies along the x-axis)

Vector B:

- x component: B_x = -(12.0 m) cos 45^{\circ}=-8.49 m

- y component: B_y = (12.0 m) sin 45^{\circ}=8.49 m

So now we can find the sum of the two vectors by adding the components along each axis:

R_x = A_x + B_x = 9.66 m - 8.49 m = 1.17 m

R_y = A_y + B_y = 0 + 8.49 m = 8.49 m

And the magnitude of the sum is given by Pythagorean theorem:

R=\sqrt{R_x^2+R_y^2}=\sqrt{(1.17 m)^2+(8.49 m)^2}=8.57 m

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<span>0.5 . k . x^2 = 0.5 . m . v^2 = m . g . ∆h </span>

<span>0.5 . 50 . (0.1^2) = 0.05 . 9.8 . ∆h </span>

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