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Otrada [13]
3 years ago
9

Can someone help me solve these four problems.

Mathematics
2 answers:
Mama L [17]3 years ago
8 0
Q= 3/2 it's a fraction 

masya89 [10]3 years ago
5 0
I only know 9.

V = 1
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Observe the sequence below 37,41,45,49
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a n  =  4 n  +  33

Step-by-step explanation:

n = number of jumps after the 0 term of '33'

aka: add 4 to the previous number

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How does understanding the characteristics of public speaking affect how you view a speech?
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I think its C

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By learning characteristics of a speech, It should be easier to determine the impact of a specific speech.

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Casey said that 40 people were surveyed. Is his answer reasonable?
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I need help with this.
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Step-by-step explanation:

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3 years ago
Thirty percent of all telephones of a certain type are submitted for service while under warranty. Of these, 70% can be repaired
Varvara68 [4.7K]

Answer:

X \sim Binom(n=10, p=0.3)

And for this case we want to find this probability:

P(X =2)

And we can use the probability mass function and we got:

P(X=2)=(10C2)(0.3)^2 (1-0.3)^{10-2}=0.233

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.3)

And for this case we want to find this probability:

P(X =2)

And we can use the probability mass function and we got:

P(X=2)=(10C2)(0.3)^2 (1-0.3)^{10-2}=0.233

4 0
3 years ago
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