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2 years ago

A PACK OF TOILET PAPER WAS ORIGINALLY $4.50 , IT COST $6.75. DID THE PRICE INCREASE OR DECREASE?

Mathematics

2 answers:

MAVERICK [17]2 years ago

8 0

It increased because the original price was 4.50

Lady bird [3.3K]2 years ago

6 0

Increase. If the toilet paper is originally 4.50 and it then is 6.50 there is a price difference. It increased.

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An equation is shown below:

lisov135 [29]

Answer: x = 1

Step-by-step explanation:

5 ( 2x - 8 ) + 15 = -15 (write the equation)

5 ( 2x - 8 ) = -30 (subtract by 15 on both sides)

2x - 8 = -6 (divide by 5 on both sides)

2x = 2 (add 8 to both sides)

x = 1 (divide by 2 on both sides)

5 0

2 years ago

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a jewelry store is having a sale. A ring is now reduced to £840. This is a saving of 40% of the original price. Work out the ori

Helen [10]

£1400

A reduction of 40% means that £840 is 60% of the original price

Divide £840 by 60 to find 1% then multiply by 100 to find original price

original price = £840 × $\frac{100}{60}$ = £1400

7 0

3 years ago

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What is the solution of the following system

AleksAgata [21]

Step-by-step explanation:

8x + 14y = 4 ...1

-6x - 7y = -10 ...2

...2 × 2 in 2 sides of the equation

-12x -14y = -20 ...3

...1 + ...3

8x + 14y +(-12x -14y) = 4 +(-20)

8x + 14y - 12x -14y = 4 - 20

-4x = -16

x = (-16)/(-4)

= 4

replace x in ...1 or ...2 you will reserve y value

and answer in the term of (x,y)

4 0

3 years ago

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Pavel [41]

$\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Explanation:</h2>

Using the quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$