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____ [38]
3 years ago
10

Find the values of the six trigonometric functions for angle θ, when AC = 26 and BC = 24.

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

The first step is to find the length of AB. By the Pythagorean Theorem:

AB=\sqrt{26^2-24^2}=\sqrt{676-576}=\sqrt{100}=10

Now, you can proceed:

\sin \theta= \dfrac{24}{26}=\dfrac{12}{13} \\\\\\\cos \theta= \dfrac{10}{26}=\dfrac{5}{13} \\\\\\\tan \theta= \dfrac{24}{10}=\dfrac{12}{5} \\\\\\\csc \theta= \dfrac{13}{12} \\\\\\\sec \theta=\dfrac{13}{5} \\\\\\\cot \theta=\dfrac{5}{12}

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Please help!! Greatly appreciated <3
Margaret [11]

Answer:

30?

Step-by-step explanation:

divide 20 by 8 and then times the answer by 12

7 0
4 years ago
Only 15 and 16 are the one I'm confused on
julia-pushkina [17]
F(2)=8 and f(5v)=25v^2+15v-2
5 0
3 years ago
An inverted pyramid is being filled with water at a constant rate of 25 cubic centimeters per second. The pyramid, at the top, h
UNO [17]

Answer:

\frac{225}{16} cm/s

Step-by-step explanation:

We are given that

\frac{dV}{dt}=25cm^3/s

Side of base=4 cm

l=w=4 cm

Height,h=12 cm

We have to find the rate at which the water level rising when the water level is 4 cm.

Volume of pyramid=\frac{1}{3}lwh=\frac{1}{3}l^2h

\frac{l}{h}=\frac{4}{12}=\frac{1}{3}

l=\frac{1}{3}h

Substitute the value

V=\frac{1}{27}h^3

Differentiate w.r.t t

\frac{dV}{dt}=\frac{3}{27}h^2\frac{dh}{dt}

Substitute the values

25=\frac{1}{9}(4^2)\frac{dh}{dt}

\frac{dh}{dt}=\frac{25\times 9}{16}=\frac{225}{16} cm/s

5 0
3 years ago
GIVING 30 POINTS
FromTheMoon [43]

Answer:

A. 502.4 cm^3

Step-by-step explanation:

r=8/2=4  cm

V=pi*r^2*h=3.14*16*10=502.4 cm^3     (A)

7 0
3 years ago
Read 2 more answers
Find the slope of line that is parallel to -2x=3y+5
In-s [12.5K]

Answer: m = -\frac{2}{3}

Step-by-step explanation:

Turn the equation into slope-intercept form: -3y = 2x + 5

Reduce: y = -\frac{2}{3}x -\frac{5}{3}

Your parallel slope is: -\frac{2}{3}

7 0
3 years ago
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