Answer:
Case 1 : Entropy of vaporization of water is 
Case 2 :Entropy of fusion of ice is 
Result : Entropy of vaporization of water is greater than entropy of fusion of ice
Explanation:
Entropy of closed system is given by 
Where
is change of entropy,
is change of heat and T is absolute temperature in kelvin
Case 1 : During vaporization of water
It is said that " 1.00 kg of water at 100 degree C is vaporized and converted to steam at 100 degree C"
Given Heat of vaporization of water is
J/kg.

m=1 kg of water
L=
J/kg.

Entropy of closed system is given by 
Where, T=100+273=373K


Thus, Entropy of vaporization of water is 
Case 2 : During fusion of ice
It is said that " 1.00 kg of ice at 0 degree C is melted and converted to water at 0 degree C"
Given Heat of fusion of ice is
J/kg.

m=1 kg of ice
L=![3.34 \times 10^{5}=334 \times 10^{3} J/kg.[tex]\Delta Q = mL = 334 \times 10^{3}](https://tex.z-dn.net/?f=3.34%20%5Ctimes%2010%5E%7B5%7D%3D334%20%5Ctimes%2010%5E%7B3%7D%20J%2Fkg.%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%5Btex%5D%5CDelta%20Q%20%3D%20mL%20%3D%20334%20%5Ctimes%2010%5E%7B3%7D)
Entropy of closed system is given by 
Where, T=0+273=273K


Thus, Entropy of fusion of ice is 
Therefore, Entropy of vaporization of water is greater than entropy of fusion of ice