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2 years ago

How much energy (in joules) is required to evaporate 0.0005 kg of liquid ammonia to vapor at the same temperature?

Physics

1 answer:

Lana71 [14]2 years ago

6 0

Answer:

685.6 J

Explanation:

The latent heat of vaporization of ammonia is

L = 1371.2 kJ/kg

mass of ammonia, m = 0.0005 Kg

Heat = mass x latent heat of vaporization

H = 0.0005 x 1371.2

H = 0.686 kJ

H = 685.6 J

Thus, the amount of heat required to vaporize the ammonia is 685.6 J.

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Two metra trains approach each other on separate but parallel tracks. one has a speed of 90 km/hr, the other 80 km/hr. initially

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The trains take 57.4 s to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

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$v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h$

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Substitute 2.71 km for d and 170 km/h for $v_A_B$

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3 years ago

Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a

skelet666 [1.2K]

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

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d = distance covered = 10 m

θ = Angle with horizontal = 20°

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W = (151 N)(10 m) Cos 20°

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