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erastova [34]
3 years ago
11

Two large, flat metal plates are separated by a distance that is very small compared to their height and width. The conductors a

re given equal but opposite uniform surface charge densities . Ignore edge effects and use Gauss's law to find for points far from the edges, the electric field between the plates. Find the field outside the plates on either side.
Physics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

E=0

Explanation:

Electric field due to each thin sheet of charge=\sigma/2\varepsilon

let us say the right plate has positive charge density \varepsilonand left sheet has a negative charge density -\varepsilon .

In the region between the plates,the electric field due to each plate is in same direction,

E=\sigma/2\varepsilon-(-\sigma/2\varepsilon)

E=\sigma/\varepsilon

in the region outside the plates, the field due to the plates is in opposite directions

E=-\sigma/2\varepsilon-(-\sigma/2\varepsilon)

E=-\sigma/2\varepsilon+\sigma/2\varepsilon

E=0

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In the periodic table notation below what information does the number 40.08 tell you
tia_tia [17]

Answer:

The number above the symbol is the atomic mass (or atomic weight). This is the total number of protons and neutrons in an atom. The number below the symbol is the atomic number and this reflects the number of protons in the nucleus of each element's atom. Every element has a unique atomic number.

Explanation:

5 0
3 years ago
The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the
Ronch [10]

Answer: 1

Explanation:

Given

Tension is the string T=44\ N

mass of object m=4\ kg

Tension is greater than the weight of the object i.e. elevator is moving upward

we can write

\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2

8 0
3 years ago
1. Of the following, the one that is not an example of a suspension is
sergiy2304 [10]

Answer: 1. C

Explanation: 2. C

8 0
4 years ago
A train departs from its station at a constant acceleration of 5m/s2. What is the speed of the train at the end of 20 seconds
Shalnov [3]

a = v/t

v = a.t

v = 5 * 20 = 100m/s

8 0
4 years ago
If an astronaut can throw a certain wrench 10.0 m vertically upward on earth, how high could he throw it on our moon if he gives
Jobisdone [24]

I think you forgot to include the acceleration due to gravity of astronauts. I assume that it is = 0.170 g. To get the answer we have to use the formula s = v0t – (1/2) At². Where s is the altitude, A is the acceleration of gravity, t is the time after throwing.

v = v0 –At

v = 0 at max altitude so v0 – At = 0

t = v0/A at max altitude

Using the formula above for the altitude:

s = v0t – (1/2) At²

s = v0(v0/A) – (1/2) A (v0/A)²

s = v0²/A – (1/2) v0²/A

s = (1/2) v0²/A

The earth: E = (1/2) v0²/g

The moon: M = (1/2)v0²(0.17g)

So, take the ratio of M/E = g/0.17g = 1/0.17 = 588

M = 5.88 E

He can throw the wrench 5.88 times higher on the moon

<span>M =5.88 (10 m) = 58.8 meters that the can throw the wrench a little over on the moon.</span>
7 0
4 years ago
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