Answer:
The car is decelerating and its acceleration is negative.
Explanation:
First thing to consider. The car traveling direction is not important to answer the question.
Second, there are two affirmations on each sentence. So, lets take definitions:
Deceleration: Reducing the acceleration, from one value to another. No matter if the acceleration for the moment is positive or negative.
Acceleration negative: the driver is applying a force to make speed=0, the sign of this force must negative in order for the car to stop, other way it will go faster. Acceleration is the change rate of speed, if the speed is going down, the total acceleration until cars stops must be negative.
To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

Here,
d = Distance between Slits
m = Order of the fringes
= Wavelength
= 

Rearranging to find the angle,




Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°
<span>The correct answer is C. divergent. Divergent boundaries are something like lines found between two tectonic plates. These constructive boundaries, or extensional boundaries, are formed and exist between two tectonic plates that move away from each other. Convergent would thus be where they meet. This is all according to the tectonic theory.</span>
Yes you are right but sometimes just because a number is bigger doesnt always make it so.
Explanation:
Relation between work and change in kinetic energy is as follows.

Also, 
=
J
=
J
Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.
w = -Fd

F =
Therefore, relation between electric field and force is as follows.
E = 
= 
=
C
Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is
C.