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djverab [1.8K]
3 years ago
15

. Two charges, Q1 and Q2 , are separated by a certain distance R. If the magnitudes of the charges are halved, and their separat

ion is also halved, then what happens to the electrical force between these charges
Physics
1 answer:
densk [106]3 years ago
6 0

Answer: Magnitude of electrical force stays the same.

Explanation:

Equation:

F_{e} =k\frac{Q_{1}Qx_{2}  }{r^{2} }

Since the magnitude of each charge is halved.

and

the separation is halved.

F_{e} =k\frac{(.5Q_{1}*.5Q_{2}  }{(.5r)^{2} }

F_{e} =k\frac{.25*Q_{1}Qx_{2}  }{.25*r^{2} }

Cancel out .25 on the numerator and denominator. Leaving the original equation.

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The lanthanides are all radioactive true or false
Oksi-84 [34.3K]

Answer:

False

Explanation:

All the lanthanides are not radioactive in nature. Just one of the lanthanides are radioactive.

  • The lanthanides belong to the f-block on the periodic table
  • Only Promethium in this group are radioactive in nature.
  • Other elements in the lanthanide series might have radioactive isotopes.
3 0
3 years ago
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.50 s, it is at
wariber [46]

Answer:

See it in the pic

Explanation:

See it in the pic

7 0
3 years ago
At 2 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
labwork [276]

Answer:

The distance between the ships changing at 6PM is 21.29Km/h

Explanation:

Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h

Given

dx/dt= 35

dy/dt= 25

dv/dt= ???? at t= 6PM - 2PM= 4

Therefore t=4

We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction

So, we use:

D^2 = (150 - x)^2 + y^2;

D^2 = (150 - 140)^2 + y^2

But ship B travels at t=4, at 4.25 =100 in the y-direction

so, let's use the equation:

D^2 = 10^2 + 100^2

= D= sqrt*(10 + 100)

Lets use 2DD' = 2xx' + 2yy'

Differentiating with respect to t we have:

D•d(D)/dt = -(10)•dx/dt + 100•dy/dt

=100.5 d(D)/dt = (-10)•35 + (100)•25

When t=4, we have x=(140-150) =10 and y=100

= D = sqrt*(10^2 + 100^2)

=100.5

= 100.5 dD/dt = 10.35 +100.25

= dD/dt = 21.29km/h

7 0
3 years ago
A train has a constant speed of 10 m/s around a track with a diameter of 45 m what is the centripal acceleration?
Bumek [7]

Answer:

a_{c}= 4.44\frac{m}{s}

Explanation:

When an object goes on a circular movement, it has a centripetal acceleration that always points toward the center of the circle, it is the responsible of the change of direction in the movement of the object. and that centripetal acceleration is related with the speed in the next way:

a_{c}=\frac{v^{2}}{r}, with v the speed, r the radius of the track that is half of the diameter (22.5 m)

a_{c}=\frac{10^{2}}{22.5}

a_{c}= 4.44\frac{m}{s}

5 0
3 years ago
How far will you travel if you walk for 10.0 minutes at a speed of 1.50 m/s?
fredd [130]

Answer:

15

Explanation:

distance = speed × time.

7 0
3 years ago
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