20 (units)
Distance formula is:
Sqrt of (x-x1)^2+(y-y1)^2
So define which coordinate is (x,y) and what (x1,y1)
I’m going to define (-10,-7) as (x,y) and (2,9) as (x1,y1)
So plug in your variables!
Sqrt(-10-2)^2+(-7-9)^2
Sqrt-12^2+-16^2
Sqrt144+256
Sqrt400
So sqrt of 400 is 20! :))
Answer: a) D = √148
m = (-5,4)
b) D = √241
m = (1, 7.5)
c) D = √20
m = (0,-4)
Step-by-step explanation:
Distance and Midpoint Formulas
distance = D = √[(x₂-x₁)² + (y₂-y₁)²]
Midpoint: m = ((x₂+x₁)/2 , (y₂+y₁)/2)
(−4, 10) and (−6, −2)
D = √[(-6-(-4))² + (-2-10)²] = √[(-6+4))² + (-2-10)²] = √[(-2))² + (-12)²] =
√[4 + 144] = √148
m = ((-6+(-4))/2 ; (-2+10)/2
m = (-10/2 ; 8/2)
m = (-5,4)
(−1, 15) and (3, 0)
D = √[(3-(-1))² + (0-15)²] = √[(3+1))² + (0-15)²] = √[(4)² + (-15)²] =
√[16 + 225] = √241
m = ((3+(-1))/2 ; (0+15)/2
m = (2/2 ; 15/2)
m = (1,7.5)
(2, −3) and (−2, −5)
D = √[(-2-2)² + ((-5)-(-3)²] = √[(-4))² + (-5+3)²] = √[(-4)² + (-2)²] =
√[16 + 4] = √20
m = (-2+2))/2 ; (-5+(-3))/2
m = (0/2 ; -8/2)
m = (0,-4)
Answer:did u ever find the answer i need it
Step-by-step explanation:
Answer:
There are no extraneous solutions
Reasoning:
An extraneous solution is a solution that isn't valid, it might be imaginary like the square root of a negative number.
first we want to isolate z:
1+sqrt(z)=sqrt(z+5)
^2 all ^2 all
(1+sqrt(z))(1+sqrt(z))=z+5
expand
1+2sqrt(z)+z=z+5
-1 -z -z -1
2sqrt(z)=4
/2 /2
sqrt(z)=2
^2 all ^2 all
z=4
Since there is one solution and it is a real number, there are no extraneous solutions.
Π=3.14
Let's start with two digits:
3.14 = 3 14/100
= 3 7/50
= 157/50
would be the approximation for that. Let's add a few more digits:
3.1415 = 3 1415/10000
= 3 283/2000
= 6283/2000
