Answer:
18
Step-by-step explanation:
2 x 3^2
2 x 9
18
We have the function:
()=−2(−3)^4+1
We need to go from this equation to the parent function x^4. To do that, we first do a vertical translation of 1 unit below. That is:
Vertical translation: f(x) - 1
= −2(−3)^4
Now, we make a horizontal shift of 3 units to the left, replacing x by x + 3:
f(x + 3) + 1 = −2()^4
Horizontal shift: f(x + 3) - 1
= −2x^4
We can make a horizontal expansion if we multiply this function by 1/2:
Horizontal expansion: ( f(x + 3) - 1 ) / 2
= -x^4
Finally, we make a reflection around the x-axis by multiplying this result by -1:
x-axis reflection: -( f(x + 3) - 1 ) / 2
= x^4
Answer:
35
Step-by-step explanation:
7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:
= 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]
Answer:
6
Step 1: Solve Square Root
Vx+3=x-3
x+3=(x-3)^2 (squared both sides)
x+3=x^2-6x+9
x+3-(x^2-6x+9)=0
(-x+1)(x-6)=0 (factor left side of equation)
-x+1=0 or x-6=0
x=1 or x=6
When you plug it in to check
1 (Doesn't Work)
6 (Work)
Therefore, 6 is your solution.
Answer:
60°
Step-by-step explanation:
ABCO is a parallelogram (opposite sides are parallel).
AO is equal to the radius of the circle, so BC must also equal the radius.
CO is equal to the radius of the circle, so AB must also equal the radius.
If we draw a line from O to B, we split the parallelogram into two triangles. Since OB is equal to the radius of the circle, each triangle is an equilateral triangle. Therefore, angle A is 60°.
