Answer:
3.01 L
Explanation:
V
1
: 2.75L
T
1
:
18
∘
C
V
2
: ?
T
2
:
45
∘
C
If you know your gas laws, you have to utilize a certain gas law called Charles' Law:
V
1
T
1
=
V
2
T
2
V
1
is the initial volume,
T
1
is initial temperature,
V
2
is final volume,
T
2
is final temperature.
Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.
Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:
2.75
291
=
V
2
318
By cross multiplying, we have...
291
V
2
= 874.5
Dividing both sides by 291 to isolate
V
2
, we get...
V
2
= 3.005...
In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.
Therefore,
V
2
= 3.01 L
<u>Answer:</u> The empirical and molecular formula of the compound is
and
respectively
<u>Explanation:</u>
We are given:
Mass of C = 3.758 g
Mass of H = 0.316 g
Mass of O = 1.251 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen = 
Moles of Oxygen = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.
For Carbon = 
For Hydrogen = 
For Oxygen = 
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of C : H : O = 4 : 4 : 1
The empirical formula for the given compound is 
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is:

We are given:
Mass of molecular formula = 130 g/mol
Mass of empirical formula = 68 g/mol
Putting values in above equation, we get:

Multiplying this valency by the subscript of every element of empirical formula, we get:

Hence, the empirical and molecular formula of the compound is
and
respectively
Answer:
The correct option is (b) "pressure".
Explanation:
Gay-Lussac's law states that the pressure of an ideal gas is directly proportional to its temperature at constant mass and volume.
Mathematically, Gay-Lussac's law is as follows :

or

Hence, the correct option is (b) "pressure".
Answer:
NH2- has two pairs of bonding and two pairs of non-bonding electrons participated in the formation of a molecule. The central nitrogen atom has two pairs of non-bonding electrons cause repulsion on both bonding pairs which pushes the bonds closer to each other. So, NH2- has a bent (angular) molecular geometry.
Explanation:
To find the Percent Composition of an atom, you use this formula:
Mass of element in the compound you're studying on ( in this case it's 5 since there is 5 Hydrogens) over the mass of the compound (which is here 79), Multiplied by 100 since you want a percent.
So we get:

So you get about:


So, the percent composition of Hydrogen in NH4HCO3 is 6.3%
Hope this Helps! :D