You add 10.0 grams of solid copper(II) phosphate, Cu3(PO4)2, to a beaker and then add 100.0 mL of water to the beaker at T = 298
K. The solid does not appear to dissolve. You wait a long time, with occasional stirring and eventually measure the equilibrium concentration of Cu2+(aq) in the water to be 5.01×10−8 M. What is the Ksp of copper(II) phosphate?
1 answer:
Answer:
1.4×10-37
Explanation:
The equation for the dissolution of the copper II phosphate is first written as shown and the ICE table is set up as also shown. S is obtained as shown and this is now used to obtain 2s and subsequently the solubility product of the calcium phosphate as shown in detail in the image attached to this solution. The step-by-step solution shows how to obtain Ksp when concentration at equilibrium is given.
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Answer:
The value of the heat capacity of the Calorimeter = 54.4
Explanation:
Given data
Heat added Q = 4.168 KJ = 4168 J
Mass of water = 75.40 gm
Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c
From the given condition
Q = ΔT +
ΔT
Put all the values in above equation we get
4168 = 75.70 × 4.18 × 11.24 + × 11.24
611.37 = × 11.24
= 54.4
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