Question

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water

Answer 1

Mass of Oxygen required : 24 grams

Further explanation

Given

3 moles of H

1.5 moles of O

3 moles of H₂O

Required

Mass of O

Solution

Reaction

2H₂ + O₂ ⇒ 2H₂O

Mass of Oxygen for 1.5 moles of O :

= mol x Ar O

= 1.5 moles x 16 g/mol

= 24 grams