Answer:
b) (5, -3)
Step-by-step explanation:
The given equations are;
![y=x-8...(1)](https://tex.z-dn.net/?f=y%3Dx-8...%281%29)
![2x+3y=1...(2)](https://tex.z-dn.net/?f=2x%2B3y%3D1...%282%29)
I prefer using substitution because of the first equation.
Put equation (1) into equation (2) to obtain;
![2x+3(x-8)=1](https://tex.z-dn.net/?f=2x%2B3%28x-8%29%3D1)
We expand the parenthesis to obtain;
![2x+3x-24=1](https://tex.z-dn.net/?f=2x%2B3x-24%3D1)
Group similar terms to get;
![2x+3x=1+24](https://tex.z-dn.net/?f=2x%2B3x%3D1%2B24)
Simplify
![5x=25](https://tex.z-dn.net/?f=5x%3D25)
Divide through by 5;
![x=\frac{25}{5}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B25%7D%7B5%7D)
![\Rightarrow x=5](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D5)
Put
into equation (1) to get;
![y=5-8](https://tex.z-dn.net/?f=y%3D5-8)
![\Rightarrow y=-3](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D-3)
The solution is (5,-3).
The correct answer is B
The answer is 0.225
I hope I helped! ♥
You can't do 140 divided by 18
or it will end up like this <span>7.77777777778</span>
Point slope form: y-y-coordinate=slope(x-x-coordinate)
slope intercept form: y=mx+b
standard form: x + y=
<h3>The distance between the points (2,3) and (5,5) is 3.6 units</h3>
<em><u>Solution:</u></em>
<em><u>Distance between two points is given by:</u></em>
![d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5Cleft%28x_%7B2%7D-x_%7B1%7D%5Cright%29%5E%7B2%7D%2B%5Cleft%28y_%7B2%7D-y_%7B1%7D%5Cright%29%5E%7B2%7D%7D)
We have to find the distance in the standard (x, y) coordinate plane between the points (2,3) and (5,5)
From given,
![(x_1, y_1) = (2, 3)\\\\(x_2, y_2) = (5, 5)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%282%2C%203%29%5C%5C%5C%5C%28x_2%2C%20y_2%29%20%3D%20%285%2C%205%29)
Substituting the values we get,
![d = \sqrt{(5-2)^2 + (5-3)^2}\\\\Simplify\\\\d = \sqrt{3^2 + 2^2}\\\\d = \sqrt{9+4}\\\\d = \sqrt{13}\\\\In\ decimal\ form\\\\d = 3.605 \approx 3.6](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%285-2%29%5E2%20%2B%20%285-3%29%5E2%7D%5C%5C%5C%5CSimplify%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B3%5E2%20%2B%202%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B9%2B4%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B13%7D%5C%5C%5C%5CIn%5C%20decimal%5C%20form%5C%5C%5C%5Cd%20%3D%203.605%20%5Capprox%203.6)
Thus distance between the points (2,3) and (5,5) is 3.6 units