Answer:
Comprehensive deductible
Step-by-step explanation:
There is nothing called Premium deductible rather deductible determines how higher of lower a premium on a subject matter of insurance can be. Deductible is the amount with the insured have to bear at loss and any excess above the loss will be compensated by the insurance company.
Comprehensive deductible is the application to only to comprehensive insurance which was what Chad had on his motor vehicle. Comprehensive insurance covers majority of peril that happens to the insured vehicle. Therefore, comprehensive deductible is the deductible Chad has to bear himself before the insurance company take other losses upon theirself..
If he had $500 deductible on his car and total repair cost $700, then he will bear the $500 while the insurance company is entitled to pay only $200 as per policy statement.
Answer:
Step-by-step explanation:
First you have to add up everything and get the answer which is 24. Then you have to consider that there are 6 yellow jelly beans. So you would have to put it as a fraction. Which would be... 6/24 hope I helped
Answer:
6) The answer is 210p - 105
7) The answer is -124q + 216
Step-by-step explanation:
1. Always Distributive Property first
6) -14 (8 - 15p) 7) -12 ( -18 + 10q)
-112 +210p 216 -120q
2. Combine like terms
6) -112 + 7 = -105 your full answer is 210p -105
7) -120q + -4q = -124q Your full answer is -124q +216.
Hope this helps.
Answer:
No they are not intergers
Step-by-step explanation:
Hope this helps
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
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