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Paraphin [41]
3 years ago
5

7. A figure skater skating across ice, who grabs another skater and brings him along the ice with her, is an example of what typ

e of collision? A. Inelastic collision B. Elastic collision C. Mass collision D. Parallel collision
Chemistry
2 answers:
blondinia [14]3 years ago
8 0

Answer:

inelastic collision

Explanation:

xenn [34]3 years ago
6 0

Answer:

The type of collision is A. Inelastic collision.

Explanation:

The macroscopic collisions are generally inelastic and do not conserve the kinetic energy, although of course the total energy is conserved. The inelastic collision is one in which the objects that collide remain together after the collision.

So, a figure skater skating across ice, who grabs another skater and brings him along the ice with her is a clear example of inelastic collision.

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a _____ is a new substance formed in a chemical reaction. a. product b. coefficient c. catalyst d. reactant
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A Product is a new substance formed in a chemical reaction
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3 years ago
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How much heat is required to raise the temperature of a 6.21 g sample of iron from 25.0 oC to 79.8 oC?
telo118 [61]

Answer:

151.1J

Explanation:

Given parameters:

Mass of iron  = 6.21g

Initial temperature of iron  = 25°C

Final temperature of iron  = 79.8°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat require to cause this temperature can be determined using the expression below;

    H  = m c (T₂ - T₁)

H is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature

    Specific heat capacity of iron 0.444J/g°C

Insert the parameters and solve;

     H  = 6.21 x 0.444 x (79.8 - 25)

     H   = 151.1J

5 0
3 years ago
What is the relationship between the Kuiper Belt and the status of Pluto today?
Xelga [282]

Pluto is a dwarf planet, but one of the largest known members, in the Kuiper belt.

The Kuiper Belt extends between 30 AU and 55 AU from the Sun

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Astronomers class Pluto as a <em>resonant Kuiper belt object</em> (KBO). Because it gets so close to Neptune, its orbit is in <em>resonance</em> with that of Neptune. Pluto makes two orbits for every three of Neptune.

4 0
3 years ago
Becky is a flower gardener. Her plants need a rich soil, full of nutrients, to grow. Propose a detailed plan of how Becky can de
WINSTONCH [101]

Answer:

In order to grow a plant one should first look and compare the climate of the local environment in which the plant grows with the climate in which the person is planning to grow the plant. Thus, in the given case, Becky should do more examinations on the kind of environment and the kind of soil in which the flower is grown generally. By finding the kind of soil, one should perform some brisk assessment on the structure and composition of the soils that will permit one to find that whether or not the planting location is suitable for the growth of the flower.  

5 0
3 years ago
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49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w
inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The  value is  \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

Explanation:

From the question we are told that

   The volume of the stock solution is  V_1   =  49.9 mL  =  0.0499 \  L  

   The concentration of the stock solution is  C_1  =  0.00292 \  M

   The volume of the diluted solution is  V_2 =  1.00 \  L

   The absorbance is  A =  0.600

Generally the from the titration equation we have that

         C_1 * V_1 =  C_2 * V_2

=>      0.00292  * 0.0499 =  C_2 * 1

=>     C_2 = 0.0001457 \  M

Generally from  Beer's law we have that

      A  =  \epsilon  * l  *  C_2

=>   \epsilon  =  \frac{A}{ l  *  C_2 }

Here  l is the length who value is  1 cm because the unit of  molar  absorptivity coefficient of the dye is M^{-1} *  cm^{-1}

So

            \epsilon  =  \frac{0.600}{ 1   * 0.0001457   }  

=>       \epsilon  =  4118.1 \  M^{-1} cm^{-1}  

4 0
3 years ago
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