Answer:
C₂ = 0.056 ppm
Explanation:
Given data:
Initial volume = 2.0 mL
Initial concentration = 7.0 ppm
Final volume = 250.0 mL
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ = Final volume
Now we will put the values in formula.
C₁V₁ = C₂V₂
7.0 ppm × 2.0 mL = C₂ × 250.0 mL
C₂ = 14.0 ppm.mL /250.0 mL
C₂ = 0.056 ppm
Answer:
a) 
b) 
c) 
Explanation:
Hello,
In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

So we proceed as follows:
a)

b)

c)

Regards.
Since you didn't have any extra information about the question I'll be presenting an example from my own textbooks that I've used.
An example of a direct observation is listening to a cricket chirp at night, and counting the number of chirps per minute.
Direct Observation is where the evaulator watches the subject in their usual habitat without disrupting or altering it.
<u>Answer:</u> The weight of water bed in pounds is 1850.16 lb
<u>Explanation:</u>
To calculate the volume of cuboid, we use the equation:

where,
V = volume of cuboid
l = length of cuboid = 210 cm
b = breadth of cuboid = 160 cm
h = height of cuboid = 25 cm
Putting values in above equation, we get:
(Conversion factor:
)
To calculate the mass of waterbed, we use the equation:

Density of waterbed = 
Volume of waterbed =
Putting values in above equation, we get:

Hence, the weight of water bed in pounds is 1850.16 lb