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4 years ago

The stability of atomic nuclei seem to be related to the ratio of _____.

2 answers:

6 0

<span>Neutrons to protons. Neutrons and protons are tiny particles that are within the nucleus. Neutrons and protons make up the nucleus of the cell and the ratio of neutrons determine the stability of the atomic nuclei. The nucleus will become unstable if the ratio of neutrons to protons are not within the appropriate amount.</span>

Zina [86]4 years ago

4 0

Answer:

neutrons to protons

Explanation:

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How many grams of iron are needed to react with 3.00 g of sulfur?

Wewaii [24]

I need really help with my work schedule for tomorrow

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3 years ago

Calculate AGrxn for this equation, rounding your

Agata [3.3K]

Answer: $\Delta G_{rxn}=130.19J$

Explanation:

The balanced chemical reaction is,

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

The expression for Gibbs free energy change is,

$\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]$

$\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]$

where,

n = number of moles

Now put all the given values in this expression, we get

$\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]$

$\Delta G_{rxn}=130.19J$

Therefore, the gibbs free energy for this reaction is, +130.19 kJ

4 0

3 years ago

A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.

hodyreva [135]

Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...(1)

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of the first object.

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

$m_1=80.00kg\\m_2=0.16kg\\u_1=0m/s\\u_2=28m/s\\v_1=v_2=V=?m/s$

Putting values in equation 1, we get:

$80(0)+0.16(28)=(0.80+0.16)V$

$V=0.056m/s$

The final velocity of man and hockey puck is 0.056 m/s.

6 0

3 years ago

Read 2 more answers

Which of the following metals is

ipn [44]

Answer:

c. iron I hope it helped.....

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3 years ago

Read 2 more answers

How many moles of gas are contained in a 50.0 L cylinder at a pressure of 100.0 atm and a temperature of 35.0°C?

grigory [225]

Answer:

n = 2 moles (1 sig-fig)

Explanation:

Using the Ideal Gas Law equation (PV = nRT), solve for n (= moles) and substitute data for ...

pressure = P(atm) = 100atm

volume =V(liters) = 50L

gas constant = R = 0.08206L·atm/mol·K

temperature = T(Kelvin) = °C + 273 = (35 + 273)K = 308K

PV = nRT => n = PV/RT = (100atm)(50L)/(0.08206L·atm/mol·K)(308K)

∴ n(moles) = 1.978moles ≅ 2 moles gas (1 sig-fig) per volume data (= 50L) that has only 1 sig-fig. (Rule => for multiplication & division computations round final answer to the measured data having the least number of sig-figs).

7 0

3 years ago