1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katen-ka-za [31]
4 years ago
15

The stability of atomic nuclei seem to be related to the ratio of _____.

Chemistry
2 answers:
Andru [333]4 years ago
6 0
<span>Neutrons to protons. Neutrons and protons are tiny particles that are within the nucleus. Neutrons and protons make up the nucleus of the cell and the ratio of neutrons determine the stability of the atomic nuclei. The nucleus will become unstable if the ratio of neutrons to protons are not within the appropriate amount.</span>
Zina [86]4 years ago
4 0

Answer:

neutrons to protons  

Explanation:

You might be interested in
Carbon monoxide (CO) _____.
cricket20 [7]

Answer:

the last one

Explanation:

All of the other ones are false

5 0
3 years ago
Read 2 more answers
The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai
Firdavs [7]

Answer:

A) N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g).

B) Kc=0.0933.

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

A)

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

B) For the calculation of Kc, we rate the equilibrium expression:

Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent x, we have:

[NH_3]=0.6M=2*x

x=\frac{0.6M}{2}=0.3M

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M

[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M

Therefore, the equilibrium constant is:

Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933

C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.

D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

Best regards.

7 0
3 years ago
What is the answer for this question?
andrew11 [14]

Answer:

See explanation, some might be graded as wrong if it's an automatic grading system but most

Explanation:

1. lose
2. valence
3. noble (Atoms don't actually always do this, but since the word gas is after the blank, it is the only option)

4. 4
5. have
6. 10

5 and 6 are a little ambiguous and could have many answers  

5 0
1 year ago
18. When a chemical reaction takes place in an open system, matter_____.
zheka24 [161]
A) can enter from the surroundings, but cannot escape to the surroundings
4 0
3 years ago
Read 2 more answers
Nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by 4c3h5n3o9 → 6n2 12co2 10h2o o2 this re
professor190 [17]
The balanced chemical reaction describing this decomposition is as follows:
<span>4c3h5n3o9 .............> 6N2 + 12CO2 +10H2O + O2

From the periodic table:
mass of oxygen = 16 grams
mass of nitrogen = 14 grams
mass of hydrogen = 1 gram
mass of carbon = 12 grams
Therefore:
mass of </span><span>C3H5N3O9 = 3(12) + 5(1) + 3(14) + 9(16) = 227 grams
mass of O2 = 2(16) = 32 grams

From the balanced chemical equation:
4(227) = 908 grams of </span>C3H5N3O9 produce 32 grams of O2. Therefore, to know the amount of oxygen produced from 4.5*10^2 grams <span>C3H5N3O9, all we need to do is cross multiplication as follows:
amount of oxygen = (4.5*10^2*32) / (908) = 15.859 grams</span>
7 0
3 years ago
Read 2 more answers
Other questions:
  • How many molds of atoms are there in each compound ?<br> 1. Al2S3<br> 2. NaNO3<br> 3. Ba(OH)2
    8·1 answer
  • How is n1 in the Rydberg equation related to the quantum number n in the Bohr model of the atom?
    13·1 answer
  • What are the products of the following general reaction?
    13·1 answer
  • Answerr fasttt pleaseee lets see who can answer
    13·1 answer
  • The structure of carbon dioxide using dots and crosses​
    14·1 answer
  • What type of eclipse is pictured below?
    5·1 answer
  • Plzzz someone help me last question
    8·1 answer
  • Please help me with this question please..
    7·1 answer
  • BRAINLIEST!!!!!! PLEASE HELP ASAP!!!!!! PLEASE ANSWER THESE!!!!! PLEASE DON'T SPAM!!!!!.​
    6·1 answer
  • 7. Indicate if the following are correct or incorrect.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!