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kifflom [539]
3 years ago
7

How did Mendeleev feel about Russian science education when he came back from Germany

Chemistry
2 answers:
krok68 [10]3 years ago
5 0

As he began to teach inorganic chemistry, Mendeleev could not find a textbook that met his needs. Since he had already published a textbook on organic chemistry in 1861 that had been awarded the prestigious Demidov Prize, he set out to write another one. The result was Osnovy khimii (1868–71; The Principles of Chemistry), which became a classic, running through many editions and many translations. When Mendeleev began to compose the chapter on the halogen elements (chlorine and its analogs) at the end of the first volume, he compared the properties of this group of elements to those of the group of alkali metals such as sodium. Within these two groups of dissimilar elements, he discovered similarities in the progression of atomic weights, and he wondered if other groups of elements exhibited similar properties. After studying the alkaline earths, Mendeleev established that the order of atomic weights could be used not only to arrange the elements within each group but also to arrange the groups themselves. Thus, in his effort to make sense of the extensive knowledge that already existed of the chemical and physical properties of the chemical elements and their compounds, Mendeleev discovered the periodic law.

professor190 [17]3 years ago
5 0

While he was researching and writing that book in the 1860s, Mendeleyev made the discovery that led to his most famous achievement. He noticed certain recurring patterns between different groups of elements and, using existing knowledge of the elements' chemical and physical properties, he was able to make further connections. He systematically arranged the dozens of known elements by atomic weight in a grid-like diagram; following this system, he could even predict the qualities of still-unknown elements. In 1869, Mendeleyev formally presented his discovery of the periodic law to the Russian Chemical Society.

HOPE THIS HELPED!!!! XD

Can I have Brainliest????? plz

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How many grams of a 23.4% by mass naf solution is needed if you want to have 1.33 moles of naf?
jenyasd209 [6]
Percentage by mass is the mass of NaF present in 100 g of the solution.
the percentage by mass of NaF is 23.4 %
this means that in 100 g of solution, mass of NaF present is 23.4 g
the number of moles of NaF present - 1.33 mol
mass of NaF - 1.33 mol x 42 g/mol = 55.9 g
when there's 23.4 g of NaF - mass of solution is 100 g
therefore when there's 55.9 g of NaF - mass of solution is 100 / 23.4 x 55.9 
= 239 g
mass of solution required is 239 g
6 0
4 years ago
When a pure sample of KNO3(s) spontaneously dissolves in water at room temperature, the solution becomes quite cold to the touch
jekas [21]

The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.

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In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.

Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.

Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.

Learn more about Potassium trioxonitrate (V) KNO₃(s) here:

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4 0
2 years ago
Helium and neon are elements in group 8a of the periodic table. How do the electron dot diagrams of these elements compare?
Ad libitum [116K]

The electron dot diagram of helium has six fewer electrons than the electron dot diagram of neon.

hope this helps!

3 0
4 years ago
Read 2 more answers
What is a mole? in your own words. <br> (6.02x10^23)
Luda [366]

Answer:

Like all units, a mole has to be based on something reproducible. A mole is the quantity of anything that has the same number of particles found in 12.000 grams of carbon-12. That number of particles is Avogadro's Number, which is roughly 6.02x1023. 1  A mole of carbon atoms is 6.02x1023 carbon atoms

Explanation:

7 0
3 years ago
At what temperature will the following reaction happen spontaneously, given that ΔH = 8.91×103 J/mol and ΔS = –219.20 J/mol·K? C
Scrat [10]
In order for a certain reaction to be spontaneous, the change in Gibb's free energy must be negative, that is:
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We can calculate dG using:
dG = dH - dS

When we plug in the given values, we see that the sign of dG will never be negative; therefore, the reaction will not be spontaneous under any conditions.
4 0
4 years ago
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