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Tpy6a [65]
3 years ago
8

What is the primary requirement for a molecule to be analyzed by Gas Chromatography?

Chemistry
2 answers:
Leviafan [203]3 years ago
6 0

Hey there!:

Gas chromatography (GC) is a type of chromatography used for separating compounds that can be vaporized without decomposition. The sample to be analyzed must be able to be vaporized in the system inlet.

So, the correct answer is A.

Hope this thelps!

BabaBlast [244]3 years ago
3 0

Answer:

b) The molecule has a molecular weight under 200 g/mole

Explanation:

The molecule has a molecular weight under 200 g/mole is the primary requirement for a molecule to be analyzed by Gas Chromatography.

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<h2>Covalent bond</h2>

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What are three main classifications of the elements
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Metals, non metals and metalloid

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A layer of paint can be used to prevent iron rusting true or false​
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true

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Which element requires the least i.e. potassium or gallium why
-Dominant- [34]

Answer:

Potassium

General Formulas and Concepts:

<u>Chem</u>

  • Reading a Periodic Table
  • Periodic Trends
  • Ionization Energy - energy required to remove an electron from a given element
  • Coulomb's Law
  • Shielding Effect
  • Z-effective and Forces of Attraction

Explanation:

The Periodic Trend for 1st Ionization Energy is increasing up and to the right. That means He would have the highest I.E and therefore take the most amount of energy to remove an electron.

Potassium and Gallium are both in Period 4. Potassium is element 19 and Gallium is element 31.

Potassium's electron configuration is [Ne] 4s¹ and Gallium's electron configurations is [Ne] 4s²3d¹⁰4p¹. Since both are in Period 4, they have the same number of core e⁻. Therefore, the shielding effect is the same.

However, since Gallium is element 31, it has 31 protons compared to Potassium, which is element 19 and has 19 protons. Gallium would have a greater Zeff than Potassium as it has more protons. Therefore, the FOA between the electrons and nucleus of Ga is much stronger than that of K. Thus, Ga requires <em>more</em> energy to overcome those FOA to remove the 4p¹ e⁻. Since K has less protons, it will have a smaller Zeff and thus less FOA between the e⁻ and nucleus, requiring <em>less</em> energy to remove the 4s¹ e⁻.

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7. I'm full of holes, yet flexible and thin. I control what gets out as well as what comes in...​
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The answer is Cell membrane
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