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dlinn [17]
3 years ago
6

germanium -66 has a half-life of 2.5 hours. you have 35 grams of radioactive material. after 16 days, how much radioactive mater

ial remains?
Chemistry
1 answer:
Maru [420]3 years ago
6 0

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

How many half-lives are in 16 days?

Multiply 16 by 24 (to get the total hours) and divide that by 2.5.

That is 153.6 half-lives.

35(0.5)^(153.6) represents the equation for this.

Simplify this and get 8.88 x 10^(-45).

There will be 2.02 x 10^(-45)g of germanium-66 sample remaining after 16 days.

Hope this helps!

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The required equation for an addition reaction between cyclohexene and Cl2 .

Cyclohexene + Cl2 → 1,2-dichlorocyclohexane

What is addition reaction ?

it is type of reaction in which one molecule combines with another molecule to form larger molecules .

addition reaction types are electrophilic , nucleophilic and free radical addition reaction .

<h3>What is free radical addition reaction ?</h3>

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2 years ago
Describe the structure of ammonium laurel sulfates refer to the given diagram. Your answer should include the type of bonding, t
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This ammonium laurel sulfates anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. It means it has a hydrophilic head and hydrophobic tail. There are ammonium ions, sulfate, and fatty acids present.

Lauryl sulfate has lauric acid attach to sulfate ions with carbon-sulfur bond, the fatty acid formed by the covalent bonds between C-C attached to hydrogens. Sulfur also bound to oxygen by covalent bonds. Nitrogen is surrounded by the four hydrogen atoms in the hydrophilic head.

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2 years ago
Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO
Irina-Kira [14]

Answer : The enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of H_2SO_4 will be,

S+H_2+2O_2\rightarrow H_2SO_4    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) S+O_2\rightarrow SO_2     \Delta H_1=-298.2

(2) SO_2+\frac{1}{2}O_2\rightarrow SO_3    \Delta H_2=-98.2

(3) SO_3+H_2O\rightarrow H_2SO_4    \Delta H_3=-130.2

(4) H_2+\frac{1}{2}O_2\rightarrow H_2O    \Delta H_4=-285.8

Now adding all the equations, we get the expression for enthalpy of formation of H_2SO_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)

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3 0
3 years ago
75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new so
kramer

Answer:

The molarity of the new solution is 0.72 M

Explanation:

Step 1: Data given

Volume of the original solution = 360 mL =.360 L

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We add 75 mL = 0.075 L

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.87 M * 0.360 L

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Step 3: Calculate new molarity

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Molarity = moles / volume

Molarity = 0.3132 moles / (0.36+0.075)

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Answer:

The answer is 12,560  

Explanation:

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