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3 years ago

Help pls I need help with this lol

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

5 0

Answer:

B. 70

Step-by-step explanation:

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What number is halfway between 60and 70

tatuchka [14]

Answer:

Step-by-step explanation:

70 - 60 = 10

10 / 2 = 5

Thus 65

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3 years ago

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American car makers produce 5,650,000 cars each year. In a report, Ben wrote that Americans made 6,550,000 cars. What mistake di

iren2701 [21]

Ben has mixed up the digit for millions and hundred thousands: he wrote 5 in the place for millions and 6 in the place for hundred thousands, but it should be the other way. I think that he should exchange those two digits in the faulty report.

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A brochure claims that the average maximum height for a certain type of plant is 0.7 m. A gardener suspects that this is not acc

larisa [96]

Answer:

As $Z$ , it is possible to reject null hypotesis. It means that the local mean height is less tha 0.7 m with a 5% level of significance.

Step-by-step explanation:

1. Relevant data:

$\mu=0.70\\N=40\\\alpha=0.05\\X=0.65\\s=0.20$

2. Hypotesis testing

$H_{0}=\mu=0.70$

$H_{1} =\mu< 0.70$

3. Find the rejection area

From the one tail standard normal chart, whe have Z-value for $\alpha=0.05$ is 1.56

Then rejection area is left 1.56 in normal curve.

4. Find the test statistic:

$Z=\frac{X-\mu_{0} }{\sigma/\sqrt{n}}$

$Z=\frac{0.65-0.70}{0.20/\sqrt{40}}\\Z=-1.58$

5. Hypotesis Testing

$Z_{\alpha}=1.56\\Z=-1.58$

$-1.58$

As $Z$ , it is possible to reject null hypotesis. It means that the local mean height is less tha 0.7 m with a 5% level of significance.

4 0

3 years ago

For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$