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Mandarinka [93]
3 years ago
9

Help pls I need help with this lol

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

B. 70

Step-by-step explanation:

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Sorry for asking so much;(
Bingel [31]
Length of line RS is probably 20 because it’s not smaller than the line it’s parallel to but it’s not equal either so the answer has to be c unless there’s a d that’s between 10-20
8 0
2 years ago
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The sum of 444 consecutive integers is 326326326.<br> What is the second number in this sequence?
Nookie1986 [14]

Answer:

82

Step-by-step explanation:

Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.

The sum of 4 consecutive numbers:

1st = x

2nd = x + 1

3rd = x + 2

4th = x + 3

The sum of 4 consecutive number is 326.

1st + 2nd + 3rd + 4th = 326

x + (x + 1) + (x + 2) + (x + 3)  = 326

Combine like terms:

4x + 6 = 326

Then we subtract 6 from both sides to isolate 4x:

4x + 6 - 6 = 326 - 6

4x = 320

Then we divide both sides by 4 to isolate x:

4x/4 = 320/4

x = 80

So the first number is 79

Now to get the second, let's just add 1.

80 + 1 = 81

Let's check if our answer would be correct:

80 + 81 + 82 + 83

= 326

5 0
2 years ago
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A computer programmer has an 18% chance of finding a bug in any given program. What is the probability that she does not find a
LiRa [457]

Answer:  (\frac{41}{50})^{10}

Step-by-step explanation:

Since, According to the question,

The chance of finding a bug in a program = 18%

Thus, the probability of finding the bug in first attempt = \frac{18}{100}=\frac{9}{50}

⇒ The probability of not finding any bug in first attempt = 1 - \frac{9}{50} =\frac{41}{50}

Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to \frac{41}{50}

Thus, the probability that she does not find a bug within the first 10 programs she examines

= \frac{41}{50}\times \frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}

= (\frac{41}{50})^{10}

5 0
3 years ago
Help i don’t understand
Nonamiya [84]

Answer:

VERTICAL LINES

Step-by-step explanation:

6 0
3 years ago
Which number is 100 times greater than 6 thousandths a) 0.6 b)0.06 c)6 d)60
Alinara [238K]

Your answer would be C.)6. Six thousandths times one hundred is six tenths.

0.006 (six thousandths) X (times) 100(one hundred) = 0.6

5 0
3 years ago
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