Answer;
FeSO4 (aq) + H2 (g)
Explanation;
The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).
The equation for the reaction is;
Fe(s) + H2SO4 (aq) = FeSO4(aq) +H2(g)
Answer:
0.80m of KOH
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, the solute is KOH and solvent is water.
Moles of 36g KOH -Molar mass: 56.1g/mol- are:
36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>
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Now, as density of water is 1g/mL, mass of 800mL of water is:
800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>
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Thus, molality is:
0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>
Answer:
43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.
Explanation:
Ideal gas law is:
PV = nRT
<em>Where P is pressure in atm</em>
<em>V is volume = 4.00L</em>
<em>n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):</em>
<em>500g * (1mol / 70.90g) = 7.052 moles</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 25°C + 273 = 298K</em>
To solve the pressure, P:
P = nRT/V
P = 7.052mol*0.082atmL/molK*298K / 4.00L
P = 43.1atm is the pressure using gas law.
Van der Waals equation is:
<em>Where a is 6.58L²atm*mol⁻²</em>
<em>b = 0.056Lmol⁻²</em>
Solving for pressure:
P = 172.323 / 3.6051 - 20.4866
P = 27.2atm using Van der Waals Law
Answer:
4
Explanation
Trailing zeros in decimals count as significant figures.
The additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL
The moles of HCl which is required to reach the equivalence point can be calculated in the way as follows.
Moles of HCl can be calculated as
Moles of HCl = 0.004 moles of Ca (OH) 2 × 2 moles of HCl / 1 moles of Ca (OH) 2
= 0.008 moles of HCl
The volume of HCl which is required to reach the equivalence point can be calculated in the way given as follows.
Volume of HCl required= 0.008 moles of HCl × 1 L / 0.24 moles of HCl × 1 ml / 10 -³ L
= 33.33 ml
The additional volume of HCl calculated as
Additional volume = required volume – actual volume
= 33.33 mL – 25 mL
= 8 . 33 mL
Thus, we calculated that the additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL.
learn more about equivalence point:
brainly.com/question/19997690
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