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PilotLPTM [1.2K]
4 years ago
11

create a flowchart that outlines when to use dimensional analysis and when to use scientific notation.

Chemistry
1 answer:
murzikaleks [220]4 years ago
7 0

Answer:

  see attached

Explanation:

Dimensional analysis is useful whenever dimensions are involved. Unless it is quite clear that all of the problem dimensions are consistent (for example, all speeds in miles per hour, or all angles in degrees), dimensional analysis can be useful for keeping the math straight.

Only units of the same dimensions can be added or subtracted. When numbers are multiplied or divided or raised to a power, dimensional analysis can help ensure that the appropriate operations are being used on appropriate numbers. It can also help ensure that dimensions are being combined properly to give appropriate derived dimensions.

__

Scientific notation is a way of writing very large or very small numbers compactly. It can also help with "order of magnitude" estimates. If an answer using SI prefixes is appropriate, or if a number can be conveniently expressed in standard form, then scientific notation is usually not required.

On the other hand, SI prefixes may not be appropriate in some cases, or a problem may specify that scientific notation be used for expressing results. In those instances, scientific notation should be used.

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Based on the calculations, the mass of Aluminum in 4.85 × 10²² atoms is equal to 2.1762 grams.

<h3>How to calculate the mass of Aluminum?</h3>

In order to determine the mass of Aluminum, we would calculate the number of atoms in 1 mole of an Aluminum atom in accordance with Avogadro's constant.

1 mole of Aluminum atom = 6.02 × 10²³ molecules

X moles of Aluminum atom = 4.85 × 10²² molecules

Cross-multiplying, we have:

X = 4.85 × 10²²/6.02 × 10²³

X = 0.0806 moles.

Mass = Molar mass × Number of moles

Mass = 27 × 0.0806

Mass = 2.1762 grams.

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For the following gases, correct the volumes to the conditions indicated. A.654 cm3 at 6 degrees Celsius and 65.3 kPa to 4 degre
leva [86]

Initial pressure of the gas = 65.3 kPa  

Initial volume of the gas = 654 cm³

Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K

Final pressure of the gas = 108.7 kPa

Final temperature of the gas = 4⁰C = 273 + 4 = 277 K

Using the combined gas law for ideal gases:

P₁V₁/T₁ = P₂V₂/T₂  

where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.

Plugging the given data into the combined gas law we have,

(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)

V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)

V₂ = 390.1 cm³


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