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liq [111]
3 years ago
14

Calculate the formula mass of each compound given below hno3

Chemistry
1 answer:
sergey [27]3 years ago
6 0
1+14+(3*16)=63g/mol
hope it helps
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What describes how the bond between two oxygen atoms is formed
HACTEHA [7]

The bond that exist between two oxygen atoms is called a double covalent bond. This bond involves the sharing of four electrons to obtain a more stable structure. This type of bond is much stronger than the single covalent bond. They are much harder to break.

4 0
4 years ago
The normal boiling point of c2cl3f3 is 47.6°c and its molar enthalpy of vaporization is 27.49 kj/mol. what is the change in entr
Goshia [24]
According to this formula when:

ΔG = ΔH - TΔS = 0

∴ ΔS = ΔH/T

∴ ΔS = n*ΔHVap / Tvap

- when n is the number of moles = mass/molar mass 

when the mass = 24.1 g 

and the molar mass = 187.3764 g/mol

by substitution: 

∴ n = 24.1 / 187.3764g/mol

      = 0.129 moles

and ΔHvap is the molar enthalpy of vaporization is 27.49 kJ/mol

and Tvap is the temperature in Kelvin = 47.6 + 273 = 320.6 K

So by substitution, we will get the ΔS the change in entropy:

∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K

      = 11 J/K
7 0
3 years ago
Does anyone know the answer???​
Dmitrij [34]
And Answer what answer would be 3.14
7 0
3 years ago
Read 2 more answers
What do you do if you receive a chemical splash to the eyes? A. Do not rub or wipe the eyes. B. All of the above. C. At the eyew
Aleksandr [31]

Explanation:

E let the water flow into the eye continuously for fifteen minutes or until medical help arrives.

5 0
4 years ago
What volume of a 0.160 MM solution of KOHKOH must be added to 550.0 mLmL of the acidic solution to completely neutralize all of
puteri [66]

The given question is incomplete. The complete question is :

What volume of 0.160 M solution of KOH must be added to 550.0 mL of the acidic solution to completely neutralize all of the 0.150 M hydrochloric acid?

Answer: Volume in liters to three significant figures is 0.516 L

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=1\\M_1=0.50M\\V_1=550.0mL\\n_2=1\\M_2=0.160M\\V_2=?

Putting values in above equation, we get:

1\times 0.150\times 550.0=1\times 0.160\times V_2\\\\V_2=516mL=0.516L   (1L=1000ml)

Thus volume in liters to three significant figures is 0.516 L

6 0
3 years ago
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